40
X=27
x = 4 and y = 7
x2-2x-10-5 = 0 x2-2x-15 = 0 (x+3)(x-5) = 0 x = -3 or x = 5
6 - x + 7 - 3x - 5 = -2x - 10 ∴ x + 3x - 2x = 6 + 7 - 5 + 10 ∴ 2x = 18 ∴ x = 9
40
X=27
x = 4 and y = 7
x2-2x-10-5 = 0 x2-2x-15 = 0 (x+3)(x-5) = 0 x = -3 or x = 5
6 - x + 7 - 3x - 5 = -2x - 10 ∴ x + 3x - 2x = 6 + 7 - 5 + 10 ∴ 2x = 18 ∴ x = 9
x = 4 and y = 7 which will satisfy both equations
6
2x+3y=13 3x-y=3 x=2
x= Negative 4
3x - 2x + 4 = 0 3x - 2x = -4 x = -4
if it is -X then X=5 if it was minus X the X=10
An equation where x equals 3.