if 3x+7 = 3 then 3x = 3-7 3x = -4 then, x = -4/3
y-3x-3 y=3x+3 A line with a slope of 3 crossing the y-axis at 3.
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.
3x=12 3x/3=12/3 x=4
2x+3=3x-3 2x-3x=-3-3 -x=-6 x=6
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
3x-3 = 6 3x = 6+3 3x = 9 x = 3
Your question is ambiguous. (3x)^3 times (3x)^3 = 27x^3 times 27x^3 = 729x^6 or, if you meant 3x^3 times 3x^3 = 9x^6
if 3x+7 = 3 then 3x = 3-7 3x = -4 then, x = -4/3
3x + 3x + 3x = 3* (3x) = 9x
3x+3=0 -3 = -3 = 3x=-3 /3 /3 x= -1
The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.The derivate of 3x is 3; the derivative of -1 is 0. So, the derivative of 3x-1 is simply 3.
3X^2 + 9X/3X factor out 3X 3X(X + 3)/3X 3X/3X = 1, so... X + 3 is the simplest form here
y-3x-3 y=3x+3 A line with a slope of 3 crossing the y-axis at 3.
3x + 4= 7 3x= 7-4 3x/3 = 3/3 x=1
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