Your question is ambiguous.
(3x)^3 times (3x)^3 = 27x^3 times 27x^3 = 729x^6
or, if you meant
3x^3 times 3x^3 = 9x^6
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
6x to the 5th power (im pretty sure)
Since you add up the 'x''s (i.e. (2x) (3x) (4x) = 24x cubed) 6x2
the answer is (3x-2)(9x squared+6x+4)
-1/6 * 3x = -3x/6 = -x/2
3x^4
3 times x times x times x
This is impossible as the variables are different
(3x)3 = 27x3
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
3x(x^2 - 5)
9x2
Cubed (3X)
6x to the 5th power (im pretty sure)
(3x)3 = 27x3 (We think the original form was simpler.)
If 3x = 81 then x = 27 and 27 cubed = 19683
If the equation is (2x)^3-3x, then the answer is -985. However, if the equation if 2(x)^3-3x, then the answer is -235.