Your question is ambiguous.
(3x)^3 times (3x)^3 = 27x^3 times 27x^3 = 729x^6
or, if you meant
3x^3 times 3x^3 = 9x^6
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
Since you add up the 'x''s (i.e. (2x) (3x) (4x) = 24x cubed) 6x2
the answer is (3x-2)(9x squared+6x+4)
Oh, what a happy little math problem we have here! To find the product of 3x cubed and 2x squared, we simply multiply the coefficients (3 and 2) to get 6, and then add the exponents of x (3 + 2) to get x to the power of 5. So, the answer is 6x to the power of 5. Isn't that just a beautiful equation?
-1/6 * 3x = -3x/6 = -x/2
3x^4
3 times x times x times x
This is impossible as the variables are different
(3x)3 = 27x3
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
3x(x^2 - 5)
(3x)(x2) = 3x3.Think of this as (3x1)(1x2). First multiply the numbers: (3)(1) = 3. next multiply the variables: (x1)(x2) = x1+2 = x3 (when you multiply powers with the same base, add the exponents)
No, (3x) and (x^3) are not the same. (3x) represents three times the value of (x), while (x^3) (or (x) cubed) represents (x) multiplied by itself three times. For example, if (x = 2), then (3x = 6) and (x^3 = 8), which are clearly different values.
Cubed (3X)
9x2
(3x)3 = 27x3 (We think the original form was simpler.)
If 3x = 81 then x = 27 and 27 cubed = 19683