5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
-4x-1-3x-4+5 = -7x-1-2x+1+6 -7x = -9x+6 2x = 6 x = 3
Fill in the missing powers of x in the dividend by having a coefficient of zero (0); then use long division: _________________ 6x³ - 3x² - 2x + 1 ________--------------------------------- 2x + 1 | 12x⁴ + 0x³ - 7x² + 0x + 1 _________ 12x⁴ + 6x³ _________ ------------- _______________ - 6x³ - 7x² _______________ - 6x³ - 3x² _______________ ------------- ____________________ - 4x² + 0x ____________________ - 4x² - 2x ____________________ ------------ ____________________________ 2x + 1 ____________________________ 2x + 1 ____________________________ -------- __________________________________0 ____________________________ ===== → (12x⁴ - 7x² + 1) ÷ (2x + 1) = 6x³ - 3x² - 2x + 1 with no remainder.
4x-1=2x+1
- 4X - 6X + 2 = 2(- 2X - 3X + 1) -------------------------that is all the factoring I can see to do here
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
(2x + 5) + (5x - 6) + (-4x + 2) = 3x + 1 There are three items so average = (3x + 1)/3 = x + 1/3
-4x-1-3x-4+5 = -7x-1-2x+1+6 -7x = -9x+6 2x = 6 x = 3
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
Fill in the missing powers of x in the dividend by having a coefficient of zero (0); then use long division: _________________ 6x³ - 3x² - 2x + 1 ________--------------------------------- 2x + 1 | 12x⁴ + 0x³ - 7x² + 0x + 1 _________ 12x⁴ + 6x³ _________ ------------- _______________ - 6x³ - 7x² _______________ - 6x³ - 3x² _______________ ------------- ____________________ - 4x² + 0x ____________________ - 4x² - 2x ____________________ ------------ ____________________________ 2x + 1 ____________________________ 2x + 1 ____________________________ -------- __________________________________0 ____________________________ ===== → (12x⁴ - 7x² + 1) ÷ (2x + 1) = 6x³ - 3x² - 2x + 1 with no remainder.
4x-1=2x+1
Your notation is hard to read. Did you mean 3x+2x-1+2x-4x+2=5? You have a lot of weird spaces that make your x's look like multiplication or something. The first step is to get variables on one side of the equation and numbers on the other. Add 1 and subtract 2 from 5, giving 3x+2x+2x-4x=4 Now, simply do the math on the variables. 3x+2x+2x-4x giving you 7x-4x which equals 3x, so that means 3x=4(from our earlier work) divide both sides by 3, 3x/3=4/3 gives us x=4/3 or x=1 1/3 or x=1.3333333 however you like.
p + q + r = (2x - 9y) + (5y + 6 - 4x) + (3x + 3y - 5) = x - y + 1
3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4
- 4X - 6X + 2 = 2(- 2X - 3X + 1) -------------------------that is all the factoring I can see to do here
Start by putting like terms on each side, so the x values on one side and the numbers on the other side. The calcualte as appropriate to give one x value and one number value. -3x + 1 + 4x + 2 -2 x - 14 + 5 x -3x + 4x - 2x + 5x + 1 + 2 - 14 4x - 11
If: y = 4x^2 -2x -1 and y = -2x^2 +3x+5 Then: 4x^2 -2x-1 = -2x^2 +3x+5 or 6x^2 -5x -6 = 0 Factorizing the above: (3x+2)(2x-3) = 0 meaning x = -2/3 or x = 3/2 By substitution points of contact are at: (-2/3, 19/9) and (3/2, 5)