x2 + 49 = x2 - (-49) = x2 - (-1)(49) = x2 - (i2)(72) = x2 - (7i)2 = (x - 7i)(x + 7i) where i is the imaginary square root of -1.
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
answer is 7i, since its the same thing as: i + (i + i + i + i + i + i)
1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i
2.2000003x10^7I think 'standard form' is 22,000,003 .
-5 - 7i
It is -4+7i or +4-7i. All that is required is to change one of the signs, it does not matter which.
[ 0 + 7i ] and [ 0 - 7i ] is.
The absolute value is sqrt(72 + 12) = sqrt(49 + 1) = sqrt(50) or 5*sqrt(2) = 7.071 approx.
x2 + 49 = x2 - (-49) = x2 - (-1)(49) = x2 - (i2)(72) = x2 - (7i)2 = (x - 7i)(x + 7i) where i is the imaginary square root of -1.
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
x2 + 49 = 0
answer is 7i, since its the same thing as: i + (i + i + i + i + i + i)
-10
-56/-71 or 56/71
To multiply complex numbers you can use the same FOIL rule that you use for multiplying binomials (First, Inside, Outside, Last).(4 - 3i)(5 + 2i) = (4)(5) +(4)(2i) - (3i)(5) - (3i)(2i) = 20 + 8i-15i - 6(i)^2= 20 -7i - 6(-1) = 20 + 6 -7i = 26 -7i.
1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i