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x2 + 49 = x2 - (-49) = x2 - (-1)(49) = x2 - (i2)(72) = x2 - (7i)2 = (x - 7i)(x + 7i) where i is the imaginary square root of -1.
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
answer is 7i, since its the same thing as: i + (i + i + i + i + i + i)
2.2000003x10^7I think 'standard form' is 22,000,003 .
1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i