9x2+6x-8 = 0 (3x+4)(3x-2) = 0 Therefore: x = -4/3 or x = 2/3
There can be no answer since there is no equation: only an expression. It is possible to factorise the expression as follows: 6x2 - 5x - 11 = 6x2 + 6x - 11x - 11 = 6x(x + 1) - 11(x + 1) = (x + 1)(6x - 11) Just to add, if you meant 6x2 - 5x - 11 = 0, then the above factorise would give you either (x+1) = 0, or (6x-11)=0, so x=-1 or 11/6
Notice that we can factor out 2x from both terms on the LH side: ... 4x2+6x=0. The greatest common factor of 4 and 6 is 2 . The greatest common factor of x2 and x ...
x2 - 6x - 27 = (x-9)(x+3)
(x-5)(x-6) so x=5,6
Ah, what a lovely little math problem we have here. When you have 6x minus 6x, you see that the two terms are the same but with opposite signs. So when you subtract them, they cancel each other out, leaving you with 0. It's like two little friends giving each other a hug and disappearing into thin air. Just a happy little zero left behind.
(3x2 - 6x)/3x = 3x(x-2)/3x = x-2, for x<>0
9x2+6x-8 = 0 (3x+4)(3x-2) = 0 Therefore: x = -4/3 or x = 2/3
There can be no answer since there is no equation: only an expression. It is possible to factorise the expression as follows: 6x2 - 5x - 11 = 6x2 + 6x - 11x - 11 = 6x(x + 1) - 11(x + 1) = (x + 1)(6x - 11) Just to add, if you meant 6x2 - 5x - 11 = 0, then the above factorise would give you either (x+1) = 0, or (6x-11)=0, so x=-1 or 11/6
6x
Notice that we can factor out 2x from both terms on the LH side: ... 4x2+6x=0. The greatest common factor of 4 and 6 is 2 . The greatest common factor of x2 and x ...
x2 - 6x - 27 = (x-9)(x+3)
x = 0,1
y + 6x - x = 0 y + 5x = 0 -y =-y 5x = -y /-1 = /-1 -5x = y m = -5 where m=slope
(x-5)(x-6) so x=5,6
When factored it is: (6x-1)(6x+1)
First, factorising, we get: x2 - 6x - 16 = (x - 8)(x + 2). Then, (x2 - 6x - 16) / (x - 8) = x + 2.