0% of 60 = 0 * 60 = 0
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
that depends on the divisor. 601 divided by 10 = 60 R1; so 1/10 =0.1 => 60.1 121 divided by 2 = 60 R1; so 1/2 =0.5 => 60.5 So, in words, 1 is divided by the original divisor and that decimal form is added to 60.
0. 60/0=0,so mathematically there are no zeros in the quantity of 60.
To calculate the volume of a frustum, you can use the formula V = (1/3) * π * h * (r1^2 + r2^2 + r1 * r2), where r1 and r2 are the radii of the two bases, h is the height, and V is the volume. Given V = 1176π mm^3 and h = 18 mm, you can substitute these values into the formula to find an equation in terms of r1 and r2. Additionally, the product of the radii, r1 * r2 = 60 mm^2, which gives you another equation. By solving these two equations simultaneously, you can find the values of r1 and r2.
0-60 mph in less than 3 sec. Top speed (on a track) better than 180mph.
You can consider a short circuit to be a resistor with R=0 Ohms. It is then clear by the equation for calculation of parallel resistance that the combined resistance of a resistor in parallel to a short circuit is 0. Consider the following example with R1= 1k Ohms and R2= 0 Ohms: Rtotal = R1*R2 / (R1+R2) = R1*0 / R1 = 0 Ohms.
Configure a static route on R1 using the IP address of the serial interface on R1. Configure a default route on R1 with the exit interface Fa0/0 on R1. Configure a static route on R1 using the IP address of S0/0/0 on R2. Configure a default route on R1 using the IP address of Fa0/0 on R2.
It is 0.
With a good rider and excellent road conditions the Yamaha YZF-R1 can do a 0-60mph time of about 2.5 seconds.
for R1-ISP network - 192.168.23.0 mask - 255.255.255.192 next hop - 192.168.23.121 (R2's S/0/0/0 IP Address) for R2-Central network - 0.0.0.0 mask - 0.0.0.0 next hop - 192.168.23.122 (R1's S/0/0/0 IP Address) Your R2-Central is right but your R1-ISP is wrong Sir! correct R1-ISP network - 172.16.0.0 mask - 255.255.254.0 next hop - 172.16.3.97
0% of 60 = 0 * 60 = 0
If the two roots are x = r1 and x = r2 then the quadratic equation is: (x - r1)(x - r2) = x2 - (r1 + r2)x + r1r2 = 0
Set up an augmented matrix and use Gaussian elimination to solve the system: 3 2 | 15 6 4 | 30 ~2 * R1 -> R1 6 4 | 30 6 4 | 30 ~ -1 * R1 + R2-> R2 6 4 | 30 0 0 | 0 ~ 1/6 * R1 -> R1 1 2/3 | 5 0 0 | 0 We can conclude two things from this: 1) The system is consistent, because there are no "bad" rows (no row reduces down to 0 ... | 1) 2) There is a free variable. The solution to the system is x + 2/3y = 5, where 'y' is free.
0 - 60 = -60
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
that depends on the divisor. 601 divided by 10 = 60 R1; so 1/10 =0.1 => 60.1 121 divided by 2 = 60 R1; so 1/2 =0.5 => 60.5 So, in words, 1 is divided by the original divisor and that decimal form is added to 60.