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0% of 60 = 0 * 60 = 0
that depends on the divisor. 601 divided by 10 = 60 R1; so 1/10 =0.1 => 60.1 121 divided by 2 = 60 R1; so 1/2 =0.5 => 60.5 So, in words, 1 is divided by the original divisor and that decimal form is added to 60.
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
0. 60/0=0,so mathematically there are no zeros in the quantity of 60.
To calculate the volume of a frustum, you can use the formula V = (1/3) * π * h * (r1^2 + r2^2 + r1 * r2), where r1 and r2 are the radii of the two bases, h is the height, and V is the volume. Given V = 1176π mm^3 and h = 18 mm, you can substitute these values into the formula to find an equation in terms of r1 and r2. Additionally, the product of the radii, r1 * r2 = 60 mm^2, which gives you another equation. By solving these two equations simultaneously, you can find the values of r1 and r2.