2.92 seconds.
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∙ 11y ago0% of 60 = 0 * 60 = 0
that depends on the divisor. 601 divided by 10 = 60 R1; so 1/10 =0.1 => 60.1 121 divided by 2 = 60 R1; so 1/2 =0.5 => 60.5 So, in words, 1 is divided by the original divisor and that decimal form is added to 60.
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
0. 60/0=0,so mathematically there are no zeros in the quantity of 60.
In order to generate the parity check matrix you must first have the generator matrix and the codeword to check and see if it is correct. 1. Place your generator in row reduction form 2. Get the basis vectors 3. Put the vectors together to get the parity check matrix 4. Check it b multiplying the codewords by the parity = 0 For an example: 2*4 Generator Matrix [1 0 1 1 0 1 1 0] Rank = 2...therefore the number of columns is 2...Rank + X = # of columns of the Generator matrix v1+v3+v4 = 0 v2+v3 = 0 v1 = -r1-r2 v2 = -r1 v3 = r1 v4 = r2 Parity = [-1 -1 -1 0 1 0 0 1]
0-60 mph in less than 3 sec. Top speed (on a track) better than 180mph.
You can consider a short circuit to be a resistor with R=0 Ohms. It is then clear by the equation for calculation of parallel resistance that the combined resistance of a resistor in parallel to a short circuit is 0. Consider the following example with R1= 1k Ohms and R2= 0 Ohms: Rtotal = R1*R2 / (R1+R2) = R1*0 / R1 = 0 Ohms.
Configure a static route on R1 using the IP address of the serial interface on R1. Configure a default route on R1 with the exit interface Fa0/0 on R1. Configure a static route on R1 using the IP address of S0/0/0 on R2. Configure a default route on R1 using the IP address of Fa0/0 on R2.
It is 0.
With a good rider and excellent road conditions the Yamaha YZF-R1 can do a 0-60mph time of about 2.5 seconds.
for R1-ISP network - 192.168.23.0 mask - 255.255.255.192 next hop - 192.168.23.121 (R2's S/0/0/0 IP Address) for R2-Central network - 0.0.0.0 mask - 0.0.0.0 next hop - 192.168.23.122 (R1's S/0/0/0 IP Address) Your R2-Central is right but your R1-ISP is wrong Sir! correct R1-ISP network - 172.16.0.0 mask - 255.255.254.0 next hop - 172.16.3.97
If the two roots are x = r1 and x = r2 then the quadratic equation is: (x - r1)(x - r2) = x2 - (r1 + r2)x + r1r2 = 0
Set up an augmented matrix and use Gaussian elimination to solve the system: 3 2 | 15 6 4 | 30 ~2 * R1 -> R1 6 4 | 30 6 4 | 30 ~ -1 * R1 + R2-> R2 6 4 | 30 0 0 | 0 ~ 1/6 * R1 -> R1 1 2/3 | 5 0 0 | 0 We can conclude two things from this: 1) The system is consistent, because there are no "bad" rows (no row reduces down to 0 ... | 1) 2) There is a free variable. The solution to the system is x + 2/3y = 5, where 'y' is free.
0% of 60 = 0 * 60 = 0
that depends on the divisor. 601 divided by 10 = 60 R1; so 1/10 =0.1 => 60.1 121 divided by 2 = 60 R1; so 1/2 =0.5 => 60.5 So, in words, 1 is divided by the original divisor and that decimal form is added to 60.
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
yes press R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2,R1,R2, then press select to complete the entire game