It is not given. If the number 115 was rounded to the nearest integer, there would be no way of determining the digit in the tenths place. If the number was written as 115.0 then the answer would be 0.
No. A whole number has no decimal part (or nothing but zeros after any decimal point present). As a recurring decimal 0.345345.... = 115/333
To the nearest ten, 120 To the nearest hundred, 100
Yes, it's just like 115 to the nearest hundred is 100. If the last two digits is less than 50 you have to round down. -15 to the nearest hundred is also 0. -95 to the nearest hundred is -100. -115 to the nearest hundred is -100. I'm not sure what -50 to the nearest hundred is, though!
To convert 114 mm to the nearest centimeter, we need to divide 114 by 10 because there are 10 millimeters in a centimeter. This gives us 11.4 cm. Since we are rounding to the nearest centimeter, and the decimal is 0.4, which is equal to or greater than 0.5, we round up to the nearest whole number. Therefore, 114 mm is equal to 12 cm when rounded to the nearest centimeter.
It is: 115
115 already is rounded to the nearest whole number...Rounded to the nearest 10, it is 120.Rounded to the nearest 100, it is 100.
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Here 80 is less than 115.which is dividend is less than divisor.80 cant be divisible by 115. quotient will come in decimals.our question is nearest no to 80 divisible by 115.so starting first number in 115 multiplication table is 115. so 115 is the answer.
3 can go into 115 a total of 38 times. This is determined by dividing 115 by 3, which equals 38.3333. Since we cannot have a fraction of a division, we round down to the nearest whole number, which is 38.
115 ÷ 14 = 8.214 or 8 times with a remainder of 3.
It is not given. If the number 115 was rounded to the nearest integer, there would be no way of determining the digit in the tenths place. If the number was written as 115.0 then the answer would be 0.
A number is divisible by 115 if it is divisible by both 5 and 23, as 115 = 5 * 23. To determine if a number is divisible by 5, you check if its last digit is 0 or 5. To check if a number is divisible by 23, you can use the divisibility rule for 23, which involves subtracting four times the last digit from the rest of the number and checking if the result is divisible by 23.
115 rounded to the nearest ten is 120
No. A whole number has no decimal part (or nothing but zeros after any decimal point present). As a recurring decimal 0.345345.... = 115/333
To the nearest ten, 120 To the nearest hundred, 100
Yes, it's just like 115 to the nearest hundred is 100. If the last two digits is less than 50 you have to round down. -15 to the nearest hundred is also 0. -95 to the nearest hundred is -100. -115 to the nearest hundred is -100. I'm not sure what -50 to the nearest hundred is, though!