No, 1023 it is not one of the multiples of the base 2 (binary) system. 1024 is. 1024 = 210. Of course 1023 can be represented in base 2 however as 1111111111.
It is equal to 6.02 x 1023
3214 - 1023 = 2191
1023
1023
The number is already rounded to a greater extent than that!
The digit after the hundreds digit is 2 which is less than 5, so the number rounds down: 1023 → 1000 to the nearest hundred.
no 3x 341 = 1023
The product of 6.02 and 1023 is 6158.46
6.0221415 × 1023
Every number is divisible by any non-zero number. However, 1023 is not evenly divisible by 2.
6.022 x 1023 is Avogadro's Number.
Avogadro's Number = Avogadro's number = 6.0221415 × 10236.02×1023 (abbreviated); this is the number of atoms, ions, molecules, or anything else in 1 mole. 0.33 moles of water would have 0.33·6.02×1023 = 1.99×1023 molecules. However water's formula is H2O, so it has 3 atoms per molecule. (0.33 moles) × (6.02×1023 molecules per mole) = 1.99×1023 molecules.1.99×1023 molecules × 3 atoms per molecule = 5.96×1023 atoms(0.33 moles) × (6.0221415 × 1023molecules per mole) = 1.987306695×1023 molecules.1.987306695×1023 molecules × 3 atoms per molecule =5.961920085 1023 atomsI would use the rounded answer, 5.96×1023 atoms
Ok let me see the answer ok am confused again
Avogadro's number is 6.022 x 1023.
Avagadro's number = 6.022 × 1023 atoms/mol0.5 mol × (6.022 × 1023) atoms/mol = 3.011 ×1023 atoms
6.022 x 1023