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Q: What is 10 P on a B C?
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10 p on a b c?

10 players on a basketball court


P equals b plus 3a plus c solve for b?

p=b+3a+c p-3a-c=b+3a-3a+c-c p-3a-c=b b=p-3a-c


10 p in g?

4 l on a c = 4 legs on a chair, 4 f on b b is 4 faces on big ben------- so what is 10 p in g


How do you divide and multiply in scientific notation?

Suppose p = a*10^x andq = b*10^y are two numbers in scientific notation.Then p*q = (a*b)*10^(x+y)where, 1


What does 50 P for a B E mean?

p=a+b+c for a


Need for madness codee?

1stColor(139,0,0) 2ndColor(139,139,139) ScaleZ(510) ScaleY(560) ScaleX(920) <p> c(27,224,63) p(10,-23,61) p(10,-20,61) p(10,-20,-61) p(10,-23,-61) </p> <p> c(27,224,63) gr(30) p(10,-20,61) p(10,18,61) p(10,18,57) p(10,-20,57) </p> <p> c(27,224,63) p(10,-10,57) p(10,0,57) p(10,0,-57) p(10,-10,-57) </p> <p> c(0,0,0) gr(30) p(10,-20,57) p(10,-10,57) p(10,-10,36) p(10,-20,36) </p> <p> c(0,0,0) gr(30) p(10,-20,33) p(10,-10,33) p(10,-10,13) p(10,-20,13) </p> <p> c(0,0,0) p(10,-20,10) p(10,-10,10) p(10,-10,-10) p(10,-20,-10) </p> <p> c(0,0,0) gr(30) p(10,-20,-13) p(10,-10,-13) p(10,-10,-34) p(10,-20,-34) </p> <p> c(0,0,0) gr(30) p(10,-20,-37) p(10,-10,-37) p(10,-10,-57) p(10,-20,-57) </p> <p> c(0,0,0) p(10,0,57) p(10,10,57) p(10,10,36) p(10,0,36) </p> <p> c(0,0,0) p(10,0,33) p(10,10,33) p(10,10,13) p(10,0,13) </p> <p> c(0,0,0) p(10,0,10) p(10,10,10) p(10,10,-10) p(10,0,-10) </p> <p> c(0,0,0) p(10,0,-13) p(10,10,-13) p(10,10,-34) p(10,0,-34) </p> <p> c(0,0,0) p(10,0,-37) p(10,10,-37) p(10,10,-57) p(10,0,-57) </p> <p> c(27,224,63) gr(30) p(10,-20,36) p(10,-10,36) p(10,-10,33) p(10,-20,33) </p> <p> c(27,224,63) p(10,-20,13) p(10,-10,13) p(10,-10,10) p(10,-20,10) </p> <p> c(27,224,63) p(10,-20,-10) p(10,-10,-10) p(10,-10,-13) p(10,-20,-13) </p> <p> c(27,224,63) gr(30) p(10,-20,-34) p(10,-10,-34) p(10,-10,-37) p(10,-20,-37) </p> <p> c(27,224,63) p(10,0,36) p(10,10,36) p(10,10,33) p(10,0,33) </p> <p> c(27,224,63) p(10,0,13) p(10,10,13) p(10,10,10) p(10,0,10) </p> <p> c(27,224,63) p(10,0,-10) p(10,10,-10) p(10,10,-13) p(10,0,-13) </p> <p> c(27,224,63) p(10,0,-34) p(10,10,-34) p(10,10,-37) p(10,0,-37) </p> <p> c(27,224,63) gr(30) p(10,-20,-57) p(10,18,-57) p(10,18,-61) p(10,-20,-61) </p> <p> c(27,224,63) p(10,18,-44) p(10,23,-47) p(10,23,-61) p(10,18,-61) </p> <p> c(27,224,63) p(10,10,57) p(10,18,57) p(10,18,-57) p(10,10,-57) </p> <p> c(27,224,63) p(10,18,44) p(10,23,47) p(10,23,61) p(10,18,61) </p> <p> c(27,224,63) p(10,18,35) p(10,23,33) p(10,23,-33) p(10,18,-35) </p> // Mirror of the 26 polygons above along the X axis: <p> c(27,224,63) p(-10,-23,61) p(-10,-20,61) p(-10,-20,-61) p(-10,-23,-61) </p> <p> c(27,224,63) p(-10,-20,61) p(-10,18,61) p(-10,18,57) p(-10,-20,57) </p> <p> c(27,224,63) p(-10,-10,57) p(-10,0,57) p(-10,0,-57) p(-10,-10,-57) </p> <p> c(0,0,0) gr(30) p(-10,-20,57) p(-10,-10,57) p(-10,-10,36) p(-10,-20,36) </p> <p> c(0,0,0) gr(30) p(-10,-20,33) p(-10,-10,33) p(-10,-10,13) p(-10,-20,13) </p> <p> c(0,0,0) p(-10,-20,10) p(-10,-10,10) p(-10,-10,-10) p(-10,-20,-10) </p> <p> c(0,0,0) gr(30) p(-10,-20,-13) p(-10,-10,-13) p(-10,-10,-34) p(-10,-20,-34) </p> <p> c(0,0,0) gr(30) p(-10,-20,-37) p(-10,-10,-37) p(-10,-10,-57) p(-10,-20,-57) </p> <p> c(0,0,0) p(-10,0,57) p(-10,10,57) p(-10,10,36) p(-10,0,36) </p> <p> c(0,0,0) p(-10,0,33) p(-10,10,33) p(-10,10,13) p(-10,0,13) </p> <p> c(0,0,0) p(-10,0,10) p(-10,10,10) p(-10,10,-10) p(-10,0,-10) </p> <p> c(0,0,0) p(-10,0,-13) p(-10,10,-13) p(-10,10,-34) p(-10,0,-34) </p> <p> c(0,0,0) gr(30) p(-10,0,-37) p(-10,10,-37) p(-10,10,-57) p(-10,0,-57) </p> <p> c(27,224,63) p(-10,-20,36) p(-10,-10,36) p(-10,-10,33) p(-10,-20,33) </p> <p> c(27,224,63) p(-10,-20,13) p(-10,-10,13) p(-10,-10,10) p(-10,-20,10) </p> <p> c(27,224,63) p(-10,-20,-10) p(-10,-10,-10) p(-10,-10,-13) p(-10,-20,-13) </p> <p> c(27,224,63) p(-10,-20,-34) p(-10,-10,-34) p(-10,-10,-37) p(-10,-20,-37) </p> <p> c(27,224,63) p(-10,0,36) p(-10,10,36) p(-10,10,33) p(-10,0,33) </p> <p> c(27,224,63) p(-10,0,13) p(-10,10,13) p(-10,10,10) p(-10,0,10) </p> <p> c(27,224,63) p(-10,0,-10) p(-10,10,-10) p(-10,10,-13) p(-10,0,-13) </p> <p> c(27,224,63) p(-10,0,-34) p(-10,10,-34) p(-10,10,-37) p(-10,0,-37) </p> <p> c(27,224,63) p(-10,-20,-57) p(-10,18,-57) p(-10,18,-61) p(-10,-20,-61) </p> <p> c(27,224,63) p(-10,18,-44) p(-10,23,-47) p(-10,23,-61) p(-10,18,-61) </p> <p> c(27,224,63) p(-10,10,57) p(-10,18,57) p(-10,18,-57) p(-10,10,-57) </p> <p> c(27,224,63) p(-10,18,44) p(-10,23,47) p(-10,23,61) p(-10,18,61) </p> <p> c(27,224,63) p(-10,18,35) p(-10,23,33) p(-10,23,-33) p(-10,18,-35) </p> // End of mirror <p> c(27,224,63) p(10,18,-61) p(10,23,-61) p(-10,23,-61) p(-10,18,-61) </p> <p> c(27,224,63) lightB p(10,12,-61) p(10,18,-61) p(7,18,-61) p(7,12,-61) </p> <p> c(27,224,63) lightB p(-10,12,-61) p(-10,18,-61) p(-7,18,-61) p(-7,12,-61) </p> <p> c(27,224,63) p(7,12,-61) p(7,18,-61) p(-7,18,-61) p(-7,12,-61) </p> <p> c(27,224,63) p(10,10,-61) p(10,12,-61) p(-10,12,-61) p(-10,10,-61) </p> <p> c(0,0,0) p(7,0,-61) p(7,10,-61) p(-7,10,-61) p(-7,0,-61) </p> <p> c(27,224,63) p(10,0,-61) p(10,10,-61) p(7,10,-61) p(7,0,-61) </p> <p> c(27,224,63) p(-10,0,-61) p(-10,10,-61) p(-7,10,-61) p(-7,0,-61) </p> <p> c(27,224,63) p(10,0,-61) p(10,-10,-61) p(-10,-10,-61) p(-10,0,-61) </p> <p> c(0,0,0) p(7,-19,-61) p(7,-10,-61) p(-7,-10,-61) p(-7,-19,-61) </p> <p> c(27,224,63) p(10,-19,-61) p(10,-10,-61) p(7,-10,-61) p(7,-19,-61) </p> <p> c(27,224,63) p(-10,-19,-61) p(-10,-10,-61) p(-7,-10,-61) p(-7,-19,-61) </p> <p> c(27,224,63) p(10,-23,-61) p(10,-19,-61) p(-10,-19,-61) p(-10,-23,-61) </p> // Mirror of the 9 polygons above along the Z axis: <p> c(27,224,63) p(10,10,61) p(10,12,61) p(-10,12,61) p(-10,10,61) </p> <p> c(0,0,0) p(7,0,61) p(7,10,61) p(-7,10,61) p(-7,0,61) </p> <p> c(27,224,63) p(10,0,61) p(10,10,61) p(7,10,61) p(7,0,61) </p> <p> c(27,224,63) p(-10,0,61) p(-10,10,61) p(-7,10,61) p(-7,0,61) </p> <p> c(27,224,63) p(10,0,61) p(10,-10,61) p(-10,-10,61) p(-10,0,61) </p> <p> c(0,0,0) p(7,-19,61) p(7,-10,61) p(-7,-10,61) p(-7,-19,61) </p> <p> c(27,224,63) p(10,-19,61) p(10,-10,61) p(7,-10,61) p(7,-19,61) </p> <p> c(27,224,63) p(-10,-19,61) p(-10,-10,61) p(-7,-10,61) p(-7,-19,61) </p> <p> c(27,224,63) p(10,-23,61) p(10,-19,61) p(-10,-19,61) p(-10,-23,61) </p> // End of mirror <p> c(27,224,63) p(10,12,61) p(10,18,61) p(7,18,61) p(7,12,61) </p> <p> c(27,224,63) p(-10,12,61) p(-10,18,61) p(-7,18,61) p(-7,12,61) </p> <p> c(255,255,255) lightF p(2,16,61) p(2,18,61) p(7,18,61) p(7,16,61) </p> <p> c(27,224,63) lightF p(-2,16,61) p(-2,18,61) p(-7,18,61) p(-7,16,61) </p> <p> c(27,224,63) p(7,12,61) p(7,16,61) p(-7,16,61) p(-7,12,61) </p> <p> c(27,224,63) p(10,18,61) p(10,23,61) p(-10,23,61) p(-10,18,61) </p> <p> c(27,224,63) p(2,16,61) p(2,18,61) p(-2,18,61) p(-2,16,61) </p> <p> c(27,224,63) p(-10,-23,61) p(10,-23,61) p(10,-23,-61) p(-10,-23,-61) </p> <p> c(130,130,130) gr(30) p(10,23,33) p(-10,23,33) p(-10,23,-33) p(10,23,-33) </p> <p> c(130,130,130) gr(30) p(10,23,-33) p(-10,23,-33) p(-10,18,-33) p(10,18,-33) </p> <p> c(130,130,130) gr(30) p(10,18,-33) p(-10,18,-33) p(-10,18,-44) p(10,18,-44) </p> <p> c(130,130,130) gr(30) p(10,18,-44) p(-10,18,-44) p(-10,23,-47) p(10,23,-47) </p> // Mirror of the 3 polygons above along the Z axis: <p> c(130,130,130) gr(30) p(10,23,33) p(-10,23,33) p(-10,18,35) p(10,18,35) </p> <p> c(130,130,130) gr(30) p(10,18,35) p(-10,18,35) p(-10,18,44) p(10,18,44) </p> <p> c(130,130,130) gr(30) p(10,18,44) p(-10,18,44) p(-10,23,47) p(10,23,47) </p> // End of mirror <p> c(130,130,130) gr(30) p(10,23,-47) p(-10,23,-47) p(-10,23,-61) p(10,23,-61) </p> <p> c(130,130,130) gr(30) p(10,23,47) p(-10,23,47) p(-10,23,61) p(10,23,61) </p> physics(50,12,50,62,50,0,0,90,10,12,12,94,50,56,4,8330) handling(76) gwgr(40) rims(140,140,140,18,10) w(-8,20,40,11,35,20) w(8,20,40,11,-35,20) gwgr(40) rims(140,140,140,18,10) w(-8,20,-40,0,35,20) w(8,20,-40,0,-35,20) stat(120,104,129,165,162)


What is the formula if you have 20 people on a basketball team 45 people on a football team 10 are on both--how many ways can a person be selected from either team?

Let P(A) = 1/10; P(A) = probability of selecting one people on a basketball team P(B) = 1/35; P(B) = probability of selecting one people on a football team P(C) = 1/10 = probability of selecting one people who plays in both teams P(D) = probability of selecting from either team. P(D) = P(A) + P(B) - P(C) P(D) = 1/10 + 1/35 - 1/10 P(D) = 1/35 or 0.0286


How many pints equal 10 cups?

There are 5 pints in 10 cups. This is because 1 pint is equivalent to 2 cups. Therefore, to convert 10 cups to pints, you divide by 2.


What is the formula to the triangle involving perimeter?

Area of triangle = sqrt[p/2*(p/2-a)*(p/2-b)*(p/2-c)] where a, b and c are the sides.


What is the perimeter of a rectangle that is 15.1 m by 16 m?

P = a + b + c + d, where a, b, c, d are sides. P = 2 × (a + b), where a and b are adjacent sides. P=2*(15.1+16) P=2*31.1 P=62.2 Answer: P= 62.2


How do you calculate in scientific notation?

Suppose p = a*10^x and q = b*10^y are two numbers in scientific notation. Then p*q = (a*b)*10^(x+y) where 1


What is 24 P of C in the H B?

Do you mean 23 P of C in the H B? 23 Pairs of chromosomes in the human body.