Chat with our AI personalities
p=b+3a+c p-3a-c=b+3a-3a+c-c p-3a-c=b b=p-3a-c
Suppose p = a*10^x andq = b*10^y are two numbers in scientific notation.Then p*q = (a*b)*10^(x+y)where, 1
p=a+b+c for a
Let P(A) = 1/10; P(A) = probability of selecting one people on a basketball team P(B) = 1/35; P(B) = probability of selecting one people on a football team P(C) = 1/10 = probability of selecting one people who plays in both teams P(D) = probability of selecting from either team. P(D) = P(A) + P(B) - P(C) P(D) = 1/10 + 1/35 - 1/10 P(D) = 1/35 or 0.0286
Area of triangle = sqrt[p/2*(p/2-a)*(p/2-b)*(p/2-c)] where a, b and c are the sides.