2c
5b+c-43b-2c+1=1-38b-c
7 x a is written as ' 7a ' In algebra Plus is shown as ' a + b ' Minus is shown as ' a - b' Multiplication is shown as 'ab' . NEVER a x b , as the 'x' may be confused with an unknown value. Division is shown as ' a/b ' , like a fraction. e.g. 6a^(2) + 5b - 2c/3 means Six multiplied to 'x' and them multiplied to 'x' again (squared). Then you 'add' five multiplied to 'b' , then you subtract two multiplied to 'c' and the whole '2c' is divided by '3'. The divisional three only refers to the '2c'. If you wanted to divided the whole expression by '3' , then you insert brackets. [ 6a^(2) + 5b - 2c ] /3 Note the position(s) of the 'square brackets'.
5b + 11 - 2b = 3b + 11
ok, let's see: (3a-2a) + (2b+5b) +(-c +3c) = a + 7b +2c I think that's right.
5b + 5b = 2 x 5b
5b+c-43b-2c+1=1-38b-c
3a + 5b - 6a - 9b = -3a - 4b
7 x a is written as ' 7a ' In algebra Plus is shown as ' a + b ' Minus is shown as ' a - b' Multiplication is shown as 'ab' . NEVER a x b , as the 'x' may be confused with an unknown value. Division is shown as ' a/b ' , like a fraction. e.g. 6a^(2) + 5b - 2c/3 means Six multiplied to 'x' and them multiplied to 'x' again (squared). Then you 'add' five multiplied to 'b' , then you subtract two multiplied to 'c' and the whole '2c' is divided by '3'. The divisional three only refers to the '2c'. If you wanted to divided the whole expression by '3' , then you insert brackets. [ 6a^(2) + 5b - 2c ] /3 Note the position(s) of the 'square brackets'.
No. 7b - 2b = 5b
5b + 11 - 2b = 3b + 11
It is 9
3a - 2b
a variable minus a number and the same variable is b-6b= -5b
2
a + 7b + 2c
(ab/b) / (4a/5b) =(ab / b) * (5b / 4a) = (5ab2 / 4ab)= 5 / (4b)
Not sure how the problem is set up as I see a space between the minus sign and the 12 but not between the minus and the 2. But, using the numbers as written: To solve for b, you must form an equation (-5b -12 -2 = 0). Next you must separate the known numbers from the unknown by adding the sum of the knowns to both sides of the equation (-5b = 14). Then divide both sides of the equation by -5 to find the value of b (b = -2.8). No no no no no. It is -5b-14 because the -5b has no relation to the others so it stays as it is and then -12-2=-14 thus getting -5b-12-2=-5b-14. Cool.