2c
5b+c-43b-2c+1=1-38b-c
7 x a is written as ' 7a ' In algebra Plus is shown as ' a + b ' Minus is shown as ' a - b' Multiplication is shown as 'ab' . NEVER a x b , as the 'x' may be confused with an unknown value. Division is shown as ' a/b ' , like a fraction. e.g. 6a^(2) + 5b - 2c/3 means Six multiplied to 'x' and them multiplied to 'x' again (squared). Then you 'add' five multiplied to 'b' , then you subtract two multiplied to 'c' and the whole '2c' is divided by '3'. The divisional three only refers to the '2c'. If you wanted to divided the whole expression by '3' , then you insert brackets. [ 6a^(2) + 5b - 2c ] /3 Note the position(s) of the 'square brackets'.
5b + 11 - 2b = 3b + 11
ok, let's see: (3a-2a) + (2b+5b) +(-c +3c) = a + 7b +2c I think that's right.
5b + 5b = 2 x 5b
5b+c-43b-2c+1=1-38b-c
3a + 5b - 6a - 9b = -3a - 4b
7 x a is written as ' 7a ' In algebra Plus is shown as ' a + b ' Minus is shown as ' a - b' Multiplication is shown as 'ab' . NEVER a x b , as the 'x' may be confused with an unknown value. Division is shown as ' a/b ' , like a fraction. e.g. 6a^(2) + 5b - 2c/3 means Six multiplied to 'x' and them multiplied to 'x' again (squared). Then you 'add' five multiplied to 'b' , then you subtract two multiplied to 'c' and the whole '2c' is divided by '3'. The divisional three only refers to the '2c'. If you wanted to divided the whole expression by '3' , then you insert brackets. [ 6a^(2) + 5b - 2c ] /3 Note the position(s) of the 'square brackets'.
No. 7b - 2b = 5b
5b + 11 - 2b = 3b + 11
It is 9
3a - 2b
a variable minus a number and the same variable is b-6b= -5b
2
a + 7b + 2c
(ab/b) / (4a/5b) =(ab / b) * (5b / 4a) = (5ab2 / 4ab)= 5 / (4b)
2a+6b