Q: What is 10bc minus 2c divided by 5b minus 1?

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5b+c-43b-2c+1=1-38b-c

5b + 11 - 2b = 3b + 11

ok, let's see: (3a-2a) + (2b+5b) +(-c +3c) = a + 7b +2c I think that's right.

5b + 5b = 2 x 5b

20a plus 14 will be 34a minus 8a minus 7 34a minus 8 is 26a minus 7 is 19a. The single b is 1b plus 6b which is 7b minus 2b equals 5b.

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5b+c-43b-2c+1=1-38b-c

3a + 5b - 6a - 9b = -3a - 4b

No. 7b - 2b = 5b

5b + 11 - 2b = 3b + 11

It is 9

3a - 2b

a variable minus a number and the same variable is b-6b= -5b

2

a + 7b + 2c

(ab/b) / (4a/5b) =(ab / b) * (5b / 4a) = (5ab2 / 4ab)= 5 / (4b)

Not sure how the problem is set up as I see a space between the minus sign and the 12 but not between the minus and the 2. But, using the numbers as written: To solve for b, you must form an equation (-5b -12 -2 = 0). Next you must separate the known numbers from the unknown by adding the sum of the knowns to both sides of the equation (-5b = 14). Then divide both sides of the equation by -5 to find the value of b (b = -2.8). No no no no no. It is -5b-14 because the -5b has no relation to the others so it stays as it is and then -12-2=-14 thus getting -5b-12-2=-5b-14. Cool.

2a+6b