x2 - 10x + 25 = 64 Or x2 - 10x + 25 = 64? If the first, move all over to 1 side; x2 - 10x + 25 - 64 = 0 x2 - 10x + -39 = 0 Then make it into quadratic equations; (x - 13)(x + 3) = 0 Therefore x = 13 or x = -3. If the second, 8x = -39 -39/8 = -9.75 = x
18
x =6 y = 8 10x = 60 8y = 64 10x + 8y = 124
Trial and error! x cubed can be 1, 8, 27, 64 etc also -1, -8, -27, -64 ... None of these are a multiple of 10 different from 51, so there is no solution in integers...
10x + 13 = 1710x = 17-1310x = 4x = 4/10x = 0.4
x2 - 10x + 25 = 64 Or x2 - 10x + 25 = 64? If the first, move all over to 1 side; x2 - 10x + 25 - 64 = 0 x2 - 10x + -39 = 0 Then make it into quadratic equations; (x - 13)(x + 3) = 0 Therefore x = 13 or x = -3. If the second, 8x = -39 -39/8 = -9.75 = x
18
x =6 y = 8 10x = 60 8y = 64 10x + 8y = 124
10x - 5x + 5x = 10x
Set it up and solve:10x² - 64 = 36 + 6x² (then separate like terms)10x² - 6x² = 36 + 64 (then simplify)4x² = 100 (then divide by 4 to solve for x²)x² = 25 (now solve for the square root of 25)x = 5 (solution)NOTEThere is another solution: x = -5When you take square roots, ALWAYS remember to include the possibility that the solution is the negative root.
If you mean: -10x+4-10x+5 then it is 9-20x when simplified
Y = 10x 10x = 40 y = 40
10x + 3 = 15 10x = 15 - 3 10x = 12 x = 1.2
-10x-6 = -12 -10x = -12+6 -10x = -6 x = 3/5
The total magnification would be 100x (10x optical zoom * 10x objective lens) for the microscope with a 10x optical and a 10x objective.
10x-8 = 2
It is: -4x-10x = -14x