3 x 7 x 7 = 147 or 1 x 3 x 49 = 147 or 49 x 6 x 1/2 = 147
42 147/7 = 21 21 x 2 = 42
147 49,3 7,7,3 3 x 7^2
2 x 423 x 284 x 216 X 147 x 12
147 = 7 x 7 x 3
3 x 7 x 7 = 147 or 1 x 3 x 49 = 147 or 49 x 6 x 1/2 = 147
1 x 147, 3 x 49, 7 x 21
147 = 3 x 7^2 or 3 x 7 x 7
42 147/7 = 21 21 x 2 = 42
147 x $2 = $294
This implies these equations: xy = 147 x + y = 147 Solve via substitution. y = 147/x x + 147/x = 147 x² + 147 = 147x x² - 147x + 147 = 0 If we graph that function and attempt to determine the zeroes of that expression, then we obtain these solutions: x = -7/2 * (-21 + √429) and x = 7/2 * (21 + √429) These solutions are also found by using the quadratic formula, which states that: x = (-b ± √(b² - 4ac))/(2a) for the equation ax² + bx + c = 0 such that a is not zero. Completing the squares also works to determine the values of x. Finally, once you have found the x values, substitute them for either of the expressions to obtain the values for y. You should get the similar values, which are: x = -7/2 * (-21 + √429) and y = 7/2 * (21 + √429) x = 7/2 * (21 + √429) and y = -7/2 * (-21 + √429)
As a product of its prime factors: 3*7*7 = 147
1 x 147, 3 x 49, 7 x 21 = 147
147 49,3 7,7,3 3 x 7^2
1, 3, 7, 21, 49, 147: 1 x 147, 3 x 49, 7 x 21, 21 x 7, 49 x 3, 147 x 1
147 x $2 = $294
2 x 423 x 284 x 216 X 147 x 12