3 x 7 x 7 = 147 or 1 x 3 x 49 = 147 or 49 x 6 x 1/2 = 147
42 147/7 = 21 21 x 2 = 42
147 49,3 7,7,3 3 x 7^2
2 x 423 x 284 x 216 X 147 x 12
147 = 7 x 7 x 3
3 x 7 x 7 = 147 or 1 x 3 x 49 = 147 or 49 x 6 x 1/2 = 147
1 x 147, 3 x 49, 7 x 21
147 = 3 x 7^2 or 3 x 7 x 7
42 147/7 = 21 21 x 2 = 42
147 x $2 = $294
This implies these equations: xy = 147 x + y = 147 Solve via substitution. y = 147/x x + 147/x = 147 x² + 147 = 147x x² - 147x + 147 = 0 If we graph that function and attempt to determine the zeroes of that expression, then we obtain these solutions: x = -7/2 * (-21 + √429) and x = 7/2 * (21 + √429) These solutions are also found by using the quadratic formula, which states that: x = (-b ± √(b² - 4ac))/(2a) for the equation ax² + bx + c = 0 such that a is not zero. Completing the squares also works to determine the values of x. Finally, once you have found the x values, substitute them for either of the expressions to obtain the values for y. You should get the similar values, which are: x = -7/2 * (-21 + √429) and y = 7/2 * (21 + √429) x = 7/2 * (21 + √429) and y = -7/2 * (-21 + √429)
As a product of its prime factors: 3*7*7 = 147
1 x 147, 3 x 49, 7 x 21 = 147
147 49,3 7,7,3 3 x 7^2
The numbers that multiply to get 147 are its prime factors. To find the prime factors of 147, we start by dividing it by the smallest prime number, which is 3. 147 รท 3 = 49. Then, we divide 49 by 7 (7 is also a prime number), which gives us 7. Therefore, the numbers that multiply to get 147 are 3, 7, and 7.
147 x $2 = $294
2 x 423 x 284 x 216 X 147 x 12