-32
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-2x2+32 -2(x2-16) -2(x+4)(x-4)
x^2 - 8x + 16 = 0(x )(x )You need two numbers that when multiplied are equal to 16, and when added are equal to 8.These two numbers are 4 and 4 (4 * 4 = 16, 4 + 4 = 16)Then you need to figure out if these are positive or negative. Since 16 is positive, you know that the numbers are either both positive or both negative. Since the 8 is negative, you know they must be negative.(x - 4)*(x - 4)
First, solve for y.y=-8xif x=2, then y=-16.
-8 x -8 = +16anything which is minus x minus = plus (- x - = +)
(-8) x (-2) = 16 (-8) + (-2) = -10 The two numbers are therefore -8 and -2.