24.04
2 times the square root of 17
1 over 2 times radical 6
You can multiply the radicands together if the radical is the same. So, the answer is radical 13*17=radical 221
Radical two times radical two is equal to two. This is because when you multiply the square root of a number by itself, you get that number back. In this case, (\sqrt{2} \times \sqrt{2} = 2).
To simplify (\sqrt{2108}), first factor the number into its prime components. The prime factorization is (2108 = 2^2 \times 527). Since (527) can be factored further into (527 = 17 \times 31), the complete factorization is (2^2 \times 17 \times 31). Thus, (\sqrt{2108} = \sqrt{2^2 \times 17 \times 31} = 2\sqrt{527}).
2 times the square root of 17
1 over 2 times radical 6
You can multiply the radicands together if the radical is the same. So, the answer is radical 13*17=radical 221
√2 x √2 = (√2)2 = 2
Radical two times radical two is equal to two. This is because when you multiply the square root of a number by itself, you get that number back. In this case, (\sqrt{2} \times \sqrt{2} = 2).
To simplify (\sqrt{2108}), first factor the number into its prime components. The prime factorization is (2108 = 2^2 \times 527). Since (527) can be factored further into (527 = 17 \times 31), the complete factorization is (2^2 \times 17 \times 31). Thus, (\sqrt{2108} = \sqrt{2^2 \times 17 \times 31} = 2\sqrt{527}).
2 times radical 5 or about 4.472135955
The expression "the radical of 4 times the radical of 7" can be written mathematically as (\sqrt{4} \times \sqrt{7}). Since (\sqrt{4} = 2), the expression simplifies to (2 \times \sqrt{7}). Thus, the final answer is (2\sqrt{7}).
17√2
The square root of 12 may be simplified to 2 times the square root of 3.
-1?
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)