1 + m is the simplest expression you can make for this problem.
1 m
1 m = 100 cm 1 cm = 0.01 m
1 m = 100cm 1/100 m = 1 cm 1/100 / 2 m = 0.5cm 1/100 x 1/2 m = 0.5cm 1/200 m = 0.5cm 5x10-3 m = 0.5cm
1 mm = 1/1000 m → 1 mm × 2 m = 1 × 1/1000 m × 2 m = 0.002 m² Or 1 m = 1000 mm → 1 mm × 2 m = 1 mm × 2 × 1000 mm = 2000 mm²
The equation for n layers is S(n) = n(n+1)(2n+1)/6It is simplest to prove it by induction.When n = 1,S(1) = 1*(1+1)(2*1+1)/6 = 1*2*3/6 = 1.Thus the formula is true for n = 1.Suppose it is true for n = m. That is, for a pyramid of m levels,S(m) = m*(m+1)*(2m+1)/6Then the (m+1)th level has (m+1)*(m+1) oranges and soS(m+1) = S(m) + (m+1)*(m+1)= m*(m+1)*(2m+1)/6 + (m+1)*(m+1)= (m+1)/6*[m*(2m+1) + 6(m+1)]= (m+1)/6*[2m^2 + m + 6m + 6]= (m+1)/6*[2m^2 + 7m + 6]= (m+1)/6*(m+2)*(2m+3)= (m+1)*(m+2)*(2m+3)/6= [(m+1)]*[(m+1)+1)]*[2*(m+1)+1]/6Thus, if the formula is true for n = m, then it is true for n = m+1.Therefore, since it is true for n =1 it is true for all positive integers.
It depends on the interpretation of the question: Trivially, (m/m)-4 = 1-4 = 1. More interestingly, m-a = 1/ma or ma = 1/m-a So, m/m-4 = m*(1/m-4) = m*(m4) = m5
5:3:1:1
1 m = 100 cm.So 1 m3 = 1 m *1 m * 1 m = 100 cm * 100 cm * 100 cm = 1,000,000 cm31 m = 100 cm.So 1 m3 = 1 m *1 m * 1 m = 100 cm * 100 cm * 100 cm = 1,000,000 cm31 m = 100 cm.So 1 m3 = 1 m *1 m * 1 m = 100 cm * 100 cm * 100 cm = 1,000,000 cm31 m = 100 cm.So 1 m3 = 1 m *1 m * 1 m = 100 cm * 100 cm * 100 cm = 1,000,000 cm3
1 m = 100 cm 1 m² = 1 m × 1 m = 100 cm × 100 cm = 10,000 cm²
1.46 m 100cm = 1 m
(m-2)/(m+2) * m/(m-1) = [(m-2)*m]/[(m+2)*(m-1)] = (m2 - 2m)/m2 + m - 2)
1 + m is the simplest expression you can make for this problem.
1 m
I presume you mean 1 km to m: (1 km)(1000 m/km)=1000 m Therefore, 1 km equals 1000 m.
1 m = 100 cm 1 cm = 0.01 m
1 m = 100cm 1/100 m = 1 cm 1/100 / 2 m = 0.5cm 1/100 x 1/2 m = 0.5cm 1/200 m = 0.5cm 5x10-3 m = 0.5cm