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It depends on the interpretation of the question:
Trivially, (m/m)-4 = 1-4 = 1.
More interestingly,
m-a = 1/ma or ma = 1/m-a
So, m/m-4 = m*(1/m-4) = m*(m4) = m5
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∙ 14y ago
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What is 2m over 4 minus m over 4?
(2m/4) - (m/4) = m/4
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
M over -4 equals 9 what is m?
m/(-4) = 9m = 9 x (-4)m = -36
What is m to the fourth power times m to the third power?
m^4 x m^3 = m^7Using a numerical example, 2^4 x 2^3 = 16 x 8 = 128 = 2^7
What is 5 over 6 minus m over 4 equals 1 over 3?
5/6 - m/4 = 1/3. First isolate the variable m, start by adding m/4 to both sides. 5/6 = 1/3 + m/4. Then subtract 1/3 from each side. 5/6 - 1/3 = m/4. Next multiply both sides by 4. 4 ( 5/6 - 1/3 ) = m. Then solve for m. 4 ( 5/6 - 2/6 ) = m. 4 ( 3/6 ) = m 4 ( 1/2 ) = m 2 = m
What is m to the power of 6 over m to the power of 10?
It is: m6 divided by m10 = m-4
What is 2m over 4 minus m over 4?
(2m/4) - (m/4) = m/4
What is m to the power of 4 divided by m to the power of six simplified?
it will be m to the power -2. assuming m as any variable.
How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?
m^4 n^5 - m^20 n^21
M over -4 equals 9 what is m?
m/(-4) = 9m = 9 x (-4)m = -36
What is m over 3 equals m plus 4 over 7?
m = 3
What is the least common denominator of 3 over 7 and 4 over m?
The LCM of 3/7 and 4/m is 7*m if m is not a multiple of 7, and m if m is a multiple of 7.
What is 4 over 7 minus 4 over m?
4/7 - 4/m need a common denominator--multiply the first term by m/m and the second by 7/7 4m/7m - 28/7m (4m-28)/7m OR 4/7 - 4/m
What is m to the fourth power times m to the third power?
m^4 x m^3 = m^7Using a numerical example, 2^4 x 2^3 = 16 x 8 = 128 = 2^7
What is 5 over 6 minus m over 4 equals 1 over 3?
5/6 - m/4 = 1/3. First isolate the variable m, start by adding m/4 to both sides. 5/6 = 1/3 + m/4. Then subtract 1/3 from each side. 5/6 - 1/3 = m/4. Next multiply both sides by 4. 4 ( 5/6 - 1/3 ) = m. Then solve for m. 4 ( 5/6 - 2/6 ) = m. 4 ( 3/6 ) = m 4 ( 1/2 ) = m 2 = m
What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?
The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.
What is m over n to the power of seven?
It is m7n-7.
