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f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2
One tenth (1/10) = 10%. Think of Percent as 'per hundred', so to find a percentage, do this: F = P% = P/100, where F is the fraction, and P is the percentage.You are given F, so solve for P. Rearrange and you have P = 100 x F, so we have P = [100 x (1/10)] = 10.
1.What is the formula for a proportionp = n / f2. p = (f / 100) * n3. p = f / n4. p = (f / n) * 100
Call F the final amount and P the principal. Then F = P(1+i)n F/(1+i)n = P
Apply the reciprocal rule: If f(x) = 1/h(x) then f'(x) = -h'(x)/(h(x))^2