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What else can I help you with?
How do you find p(b) when p(a) is 23 p(ba) is 12 and p(a U b) is 45 and is a dependent event?
There are symbols missing from your question which I cam struggling to guess and re-insert. p(a) = 2/3 p(b ??? a) = 1/2 p(a ∪ b) = 4/5 p(b) = ? Why use the set notation of Union on the third given probability whereas the second probability has something missing but the "sets" are in the other order, and the order wouldn't matter in sets. There are two possibilities: 1) The second probability is: p(b ∩ a) = p(a ∩ b) = 1/2 → p(a) + p(b) = p(a ∪ b) + p(a ∩ b) → p(b) = p(a ∪ b) + p(a ∩ b) - p(a) = 4/5 + 1/2 - 2/3 = 24/30 + 15/30 - 20/30 = 19/30 2) The second and third probabilities are probabilities of "given that", ie: p(b|a) = 1/2 p(a|b) = 4/5 → Use Bayes theorem: p(b)p(a|b) = p(a)p(b|a) → p(b) = (p(a)p(b|a))/p(a|b) = (2/3 × 1/2) / (4/5) = 2/3 × 1/2 × 5/4 = 5/12
Formulas on Percentage Base and Rate?
P=B×RB=P÷RR=P÷B
How might two probabilities be added?
If A and B are two events then P(A or B) = P(A) + P(B) - P(A and B)
What is the Formula for odds for either of two events?
If A and B are mutually exclusive event then Probability of A or B is P(A)+P(B). If they are not mutually exclusive then it is that minus the probability of the P(A)+P(B) That is to say P( A or B)= P(A)+P(B)- P(A and B). Of course it is clear that if they are mutually exclusive, P(A and B)=0 and we have the first formula.
What is the missing probability P(A)0.35 P(AorB)0.55 P(B)?
To find the missing probability ( P(B) ), you can use the formula for the probability of the union of two events: ( P(A \cup B) = P(A) + P(B) - P(A \cap B) ). Assuming ( P(A \cap B) = 0 ) (which is common unless otherwise specified), you can rearrange the equation: ( P(B) = P(A \cup B) - P(A) = 0.55 - 0.35 = 0.20 ). Thus, ( P(B) = 0.20 ).
What does 24 b b in a p mean?
24 black birds in a pie
What is 24 b in a p?
there are 24 blackbirds in a pie!!!!!!!!
24 b b b in a p?
24 black birds baked in a pie. From the nursery rhyme Sing A Song Of Sixpence.
24 B B in a P?
Blackbirds Baked in a Pie That's my Guess
What is 24 BB in a P short for?
24 blackbirds baked in a pie? some times seen as 4 & 20 B B B in a pie.
What is 24 P of C in the H B?
Do you mean 23 P of C in the H B? 23 Pairs of chromosomes in the human body.
What does this ditloid mean 24 B B in a P?
Blackbirds Baked in a Pie. Should really be 4 and 20!
If A and B are independent events then are A and B' independent?
if P(A)>0 then P(B'|A)=1-P(B|A) so P(A intersect B')=P(A)P(B'|A)=P(A)[1-P(B|A)] =P(A)[1-P(B)] =P(A)P(B') the definition of independent events is if P(A intersect B')=P(A)P(B') that is the proof
How do you find p(b) when p(a) is 23 p(ba) is 12 and p(a U b) is 45 and is a dependent event?
There are symbols missing from your question which I cam struggling to guess and re-insert. p(a) = 2/3 p(b ??? a) = 1/2 p(a ∪ b) = 4/5 p(b) = ? Why use the set notation of Union on the third given probability whereas the second probability has something missing but the "sets" are in the other order, and the order wouldn't matter in sets. There are two possibilities: 1) The second probability is: p(b ∩ a) = p(a ∩ b) = 1/2 → p(a) + p(b) = p(a ∪ b) + p(a ∩ b) → p(b) = p(a ∪ b) + p(a ∩ b) - p(a) = 4/5 + 1/2 - 2/3 = 24/30 + 15/30 - 20/30 = 19/30 2) The second and third probabilities are probabilities of "given that", ie: p(b|a) = 1/2 p(a|b) = 4/5 → Use Bayes theorem: p(b)p(a|b) = p(a)p(b|a) → p(b) = (p(a)p(b|a))/p(a|b) = (2/3 × 1/2) / (4/5) = 2/3 × 1/2 × 5/4 = 5/12
What is the product rule and the sum rule of probability?
Sum Rule: P(A) = \sum_{B} P(A,B) Product Rule: P(A , B) = P(A) P(B|A) or P(A, B)=P(B) P(A|B) [P(A|B) means probability of A given that B has occurred] P(A, B) = P(A) P(B) , if A and B are independent events.
What military aircraft had Browning 50 caliber machine guns mounted on or in them in World War 2?
A LOT. all U.S. aircraft had .50 cals The P-51, P-38, P-47, B-25, B-17, B-29, A-20, B-24, P-39 etc.
What is the formula for inclusive events?
The probability of inclusive events A or B occurring is given by P(A or B) = P(A) + P(B) - P(A and B), where P(A) and P(B) represent the probabilities of events A and B occurring, respectively.
