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What is 24 P of C in the H B?
Do you mean 23 P of C in the H B? 23 Pairs of chromosomes in the human body.
What is 24 b in a p?
there are 24 blackbirds in a pie!!!!!!!!
What is the value of a-b if a is 24 and b is 6?
If a = 24 and b = 6, then a - b = 24 - 6 = 18
What does 23 P OF C IN The h b mean?
23 pairs of chromosomes in the human body
If a divides b and b divides a then a is equal to b?
If a divides b and b divides a then either a is equal to b or a is equal to -b. Additional note: if a divides b, there exist a p such that ap=b. and if b divides a, there exist a q such that a=bq. then ap=(bq)p=b => b(1-pq)=0 => pq=1 since b!=0 => p=q=1 or p=q=-1 => a=b or a=-b
What is 24 P of C in the H B?
Do you mean 23 P of C in the H B? 23 Pairs of chromosomes in the human body.
What does this ditloid mean 24 B B in a P?
Blackbirds Baked in a Pie. Should really be 4 and 20!
What is 24 b in a p?
there are 24 blackbirds in a pie!!!!!!!!
What does 50 P for a B E mean?
p=a+b+c for a
24 b b b in a p?
24 black birds baked in a pie. From the nursery rhyme Sing A Song Of Sixpence.
24 B B in a P?
Blackbirds Baked in a Pie That's my Guess
What is 24 BB in a P short for?
24 blackbirds baked in a pie? some times seen as 4 & 20 B B B in a pie.
If A and B are independent events then are A and B' independent?
if P(A)>0 then P(B'|A)=1-P(B|A) so P(A intersect B')=P(A)P(B'|A)=P(A)[1-P(B|A)] =P(A)[1-P(B)] =P(A)P(B') the definition of independent events is if P(A intersect B')=P(A)P(B') that is the proof
How do you find p(b) when p(a) is 23 p(ba) is 12 and p(a U b) is 45 and is a dependent event?
There are symbols missing from your question which I cam struggling to guess and re-insert. p(a) = 2/3 p(b ??? a) = 1/2 p(a ∪ b) = 4/5 p(b) = ? Why use the set notation of Union on the third given probability whereas the second probability has something missing but the "sets" are in the other order, and the order wouldn't matter in sets. There are two possibilities: 1) The second probability is: p(b ∩ a) = p(a ∩ b) = 1/2 → p(a) + p(b) = p(a ∪ b) + p(a ∩ b) → p(b) = p(a ∪ b) + p(a ∩ b) - p(a) = 4/5 + 1/2 - 2/3 = 24/30 + 15/30 - 20/30 = 19/30 2) The second and third probabilities are probabilities of "given that", ie: p(b|a) = 1/2 p(a|b) = 4/5 → Use Bayes theorem: p(b)p(a|b) = p(a)p(b|a) → p(b) = (p(a)p(b|a))/p(a|b) = (2/3 × 1/2) / (4/5) = 2/3 × 1/2 × 5/4 = 5/12
What military aircraft had Browning 50 caliber machine guns mounted on or in them in World War 2?
A LOT. all U.S. aircraft had .50 cals The P-51, P-38, P-47, B-25, B-17, B-29, A-20, B-24, P-39 etc.
What is the product rule and the sum rule of probability?
Sum Rule: P(A) = \sum_{B} P(A,B) Product Rule: P(A , B) = P(A) P(B|A) or P(A, B)=P(B) P(A|B) [P(A|B) means probability of A given that B has occurred] P(A, B) = P(A) P(B) , if A and B are independent events.
What does the B in B-17 mean?
The B in B-17 probably means Bomber since that was what it was. Same for the B-24, 25, 26, and 29 There is another question on this site that list the prefixes for all WW2 aircaft. B = bomber P = pursuit F = fighter O = observation etc
