5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
x = -2/3,7/6
(c - z)(c^2 + cz + z^2)
2
X = 2, 2 X 2 X 2 = 8 - 8 = 0
(x - 4)(x^2 + 4x + 16)
minus the cube root of 2, or about -1.26
-2, 1.74 and 0.46
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
x 3-8
so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
72 minus the root of squared minus equals 72 but you have to be smart to know that the minimum circumference s 56 there you go
it doesn't it equals 4
The correct equation is a^3 - a^2*cos(a) - 6cos(a) = 0 which gives cos(a) = a^3/(a^2 + 6) This is not a simple equation to solve. In any case, before attempting a solution, it is necessary to know whether a is measured in degrees or radians.
x = -2/3,7/6