Factor out the GCF and get X(X2-X+1).
(x - 1)(x^2 + x + 1)
(x3 - 8) is factored thus: (x - 2)(x2 + 2x + 4) The easiest way to do this is to remember the formula: (a3 - b3) = (a - b)(a2 + ab + b2)
(x + 6)(x - 6)
n(2n - 1)(2n + 7)
(x - 1)(x^2 + x + 1)
(4x - 3)(16x^2 + 12x + 9)
(x - 5)(x^2 + 5x + 25)
x³ - x² + x - 3 (x² + 1)(x - 1) - 2
(xy - 7)(x^2y^2 + 7xy + 49)
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
The given expression is 2x^3 - x - 3. It is a polynomial of degree 3 with the leading term 2x^3.
To factor out the expression: x2y-y3 First factor out one "y": y(x2-y2) The expression x2-y2 is a difference of squares, which factors as well: (y)(x-y)(x+y) This is the simplest factoring of the original expression.
x cubed minus 216
t3-1/27
There are no factors with rational coefficients.
(c - z)(c^2 + cz + z^2)