14√2
14 rad. 2
6 radical 2
2 radical 11 the square root of 44. 44/2 = 22 radical 2 x 22 radical 2 x 2 x 11 Since 2 is under the radical twice you can take it out 2 radical 11
(a-2(ab)1/2+b)/(a-b)
14√2
radical(14)*radical(2) = 2*radical(7) Without further information available we will consider only the square roots. The square roots of 14 are +3.741 and -3.741, similarly the square roots of 2 are+1.414 and -1.414 and so we can have four products 1) (+3.741) X (+1.414) = +5.155 2) (-3.741) x (+1.414) = -5.155 3) (+3.741) x (-1.414) = -5.155 4) (-3.741) x (-1.414) = +5.155 Expressions 1 and 4 are equal, expressions 2 and 3 are equal. Hence the product of radical 14 times radical 2 can be +5.155 or -5.155
put it to the power of 1/2 141/2 = 3.74
I assume you mean x(squared) + 4x - 10. Solving this isn't extremely difficult if you know the quadratic formula. first of all, remember the form ax(squared) + bx + c you are currently in that form. so, the formula is (-b +OR- radical(b(squared) - 4ac)) /2a so, using the formula, you will get (-4 + or - radical(16 - 4(1)(-10)))/2(1) this simplifies to (-4 + or - radical(56)) / 2 this can simplify to (-4 + or - radical(4) * radical(14)) / 2 the 2 in the denominator cancels out with the -4 and the 2(comes from radical(4)) in the numerator. this leaves us with -2 + or - radical(14) these are the two solutions. x= -2 + radical(14) x = -2 - radical(14) this may seem complex since it's hard to explain in this way, but I promise you will understand it. here is an easier to understand version of the quadratic formula.
2 square root of 14
14 rad. 2
No, it is not.
2
-3*radical(2)*radical(50) = -3*radical(2*50) = -3*radical(100) = -3*10 = -30
6 radical 2
12 radical 2 you multiply 6 and 2 :)
2 radical(8) = 4 radical(2)