(a + x^2)(b + y^2)
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
(a + 2 - b) (a + 2 + b)
2
x^2+x^2=2x^2
104
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
(a + x^2)(b + y^2)
1 squared plus 8 squared or 4 squared plus 7 squared
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
(a + 2 - b) (a + 2 + b)
2^2 + 3^2 = 4 + 9 = 13
8 = 4 + 4 = 2² + 2²
(x+y)2
When the sum of a number plus 3 is squared, it is 11 more than the sum of the number plus 2 when squared.
2 squared plus 2 squared equals 16 because 2 squared is 4 times 4 equals 16. Math: 4x4=16 so your answer is 16 :)!
(a+b)2