260
65 times
65 x 2
130 ÷ 50 = 2 with remainder 30.
5 times 13 times 2 = 2 times 5 times 13 = 10 times 13 = 130
The highest common multiple (HCM) of two numbers is the smallest multiple that is a common multiple of both. For 120 and 130, the HCM is found by calculating the least common multiple (LCM). The prime factorization of 120 is (2^3 \times 3 \times 5) and for 130 it is (2 \times 5 \times 13). The LCM is (2^3 \times 3 \times 5 \times 13 = 1560), so the HCM of 120 and 130 is 1560.
Well, isn't that a happy little math question! If we take 130 and divide it by 2, we find that 2 goes into 130 a total of 65 times. Just imagine each division as a little tree in a beautiful forest of numbers. Happy dividing!
130
65 times
65 x 2
130 / 50 = 2 with a remainder of 30.
130 ÷ 50 = 2 with remainder 30.
130 ÷ 8 = 16 with remainder 2
13x2x5=130
260 ÷ 2 = 130
5 times 13 times 2 = 2 times 5 times 13 = 10 times 13 = 130
The highest common multiple (HCM) of two numbers is the smallest multiple that is a common multiple of both. For 120 and 130, the HCM is found by calculating the least common multiple (LCM). The prime factorization of 120 is (2^3 \times 3 \times 5) and for 130 it is (2 \times 5 \times 13). The LCM is (2^3 \times 3 \times 5 \times 13 = 1560), so the HCM of 120 and 130 is 1560.
You can find the prime factorization of 130: 130 = 2*5*13 Therefore the answer is 1. Or you can skip a step. Just divide 130 by 2. You get 65, which is an odd number. Therefore there is only 1 factor of 2 in the factorization of 130.