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37 Fit the cubic: Un = (2n3 - 9n2 + 16n + 6)/3 for n = 1, 2, 3, ...
There are many possible answers. One possibility is Un = (2n3 - 3n2 + n + 24)/6
25* * * * *24Using t(n) = (2n3 - 9n2 + 25n - 6)/6 for n = 1, 2, 3, ...Take your pick. I have given the justification for my answer.
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There are infinitely many possible rules: there is one or more polynomials of every degree≥ 3 and then there are other possible functional relationships.There is only one polynomial of degree 3 and that isUn= (2n3- 15n2+ 19n + 12)/3 where n = 1, 2, 3, ...