That factors to (2n + 1)(n + 2)
Oh, dude, adding n squared plus n squared is like adding apples to apples, you know? It's just like, you take two n squared terms and you add them together to get 2n squared. It's not rocket science, man. Just double up those n squares and you're good to go.
16, 36, 64, 100, 144, 196 etc The square of any even number is a multiple of 4 because an even number is 2n and (2n) squared is 4 (n squared).
4n
7+2n
n(2n - 1)(2n + 7)
It is: 2n^2 -5n -42 equals (2n+7)(n-6) when factored
It is 2n^3 + 7n^2 - 13n + 3
That factors to (2n + 1)(n + 2)
6n(2n - 3)
m2 - 4mn - 12n2 = m2 - 6mn + 2mn - 12n2 = m(m - 6n) + 2n(m - 6n) = (m + 2n)(m - 6n)
n is 2. To solve, do the division: . . . . . . . . .x2 +. 3x + (6-2n) . . . -------------------------- x-2 | x3 + x2 - 2nx + n2 . . . . .x3 -2x2 . . . . .-------- . . . . . . . .3x2 - 2nx . . . . . . . .3x2 - . 6x . . . . . . . .---------- . . . . . . . . . (6-2n)x + n2 . . . . . . . . . (6-2n)x - 2(6-2n) . . . . . . . . . ---------------------- . . . . . . . . . . . . . . . .n2 + 2(6-2n) But this remainder is known to be 8, so: n2 + 2(6-2n) = 8 ⇒ n2 - 4n + 4 = 0 ⇒ (n - 2)2 = 0 ⇒ n = 2
Oh, dude, adding n squared plus n squared is like adding apples to apples, you know? It's just like, you take two n squared terms and you add them together to get 2n squared. It's not rocket science, man. Just double up those n squares and you're good to go.
16, 36, 64, 100, 144, 196 etc The square of any even number is a multiple of 4 because an even number is 2n and (2n) squared is 4 (n squared).
6n2 + 16n can be factorised to give 2n(3n + 8) so the highest factor is 2n.
If the given equation were factorized it would be: 2n2 + 4n = 2n(n+1) Another Answer:- The given expression when factored is 2n(n+2)
5m+2n, n-3m, 7-3n (5m+2n)+(n-3m)+(7-3n)=2m+7