n * 2n = 2n2
2n is 2 times n.
2n
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
To multiply the expressions (6n) and (2n), you multiply the coefficients (6 and 2) and the variable terms. This results in (6 \times 2 = 12) and (n \times n = n^2). Therefore, (6n \times 2n = 12n^2).
n+2/n=110 times by n on both sides n^2+2n=110n -2n -2n n^2=100n divide by n n=100 I think this may be right. Good luck!
2n is 2 times n.
2n
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
To multiply the expressions (6n) and (2n), you multiply the coefficients (6 and 2) and the variable terms. This results in (6 \times 2 = 12) and (n \times n = n^2). Therefore, (6n \times 2n = 12n^2).
let the number be n. Then: 2n = 3n ⇒ 2n - 2n = 3n - 2n ⇒ 0 = n ie, the number is zero.
Meiosis produces haploid gametes which have the ' n ' symbol.
Suppose the number is N. Then 2N - 4 = 47 2N = 51 N = 25.5
n+2/n=110 times by n on both sides n^2+2n=110n -2n -2n n^2=100n divide by n n=100 I think this may be right. Good luck!
1/2n + 1/(2n+2) = 1/2*[(1/n + 1/(n+1)] = 1/2*(2n+1)/[n*(n+1)] or (2n+1)/[2*n*(n+1)]
The probability will b 0.5. since a coin tossed n times has 2n no. of desired results, among which only half that is n times it can b tail. Hence P = n/2n i.e 0.5.
300 - 2n = 126 2n = 174 n = 87
5n - 9 = 2n + 6 : Add 9 to both sides 5n = 2n + 15 : Subtract 2n from both sides 3n = 15 : Divide both sides by 3 n = 5