3p-pq 2pr factorized = 1
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To factorize the expression 3p - pq - 2pr, we need to look for common factors among the terms. The common factor among the terms is p. Factoring out p gives us: p(3 - q - 2r). So, the factorized form of 3p - pq - 2pr is p(3 - q - 2r).
74*22 it was already prime factorized.
It is: 2(11x+3) when factorized
16a4-24a2b3 plus 9b6, this equation cannot be factorized. Kindly check again and re-post.
Fundamental theorem of arithmetic :- Every composite number can be expressed (factorized) as a product of primes, and this factorization is unique . apart from the other in which factors occur.
b2 + 16b + 64 can be factorized to (b+8)(b+8). If they were equal to zero as in b2 + 16b + 64=0 then b = -8.