2x-1=-32x=-3+1x=-2/2x=-1
(2x + 3)(x - 2)
y = 2x + 1 1. Make a table: x = -2; y = -3y = 2x + 1y = 2(-2) + 1 = -4 + 1 = -3 x = -1; y = -1y = 2x + 1y = 2(-1) + 1 = -2 + 1 = -1x = 0; y = 1y = 2x + 1y = 2(0) + 1 = 0 + 1 = 1 x = 1; y = 3y = 2x + 1y = 2(1) + 1 = 2 + 1 = 3 x = 2; y = 5y = 2x + 1y = 2(2) + 1 = 4 + 1 = 5 2. Plug the points (-2, -3), (-1, -1), (0, 1), (1, 3), and (2, 5) in a xy-coordinate system. 3. Draw a line which passes through those points. Thus, the line drawn is the graph of the function y = 2x + 1
x-3 = 2x+4 add 3 to both sides x = 2x+7 subtract 2x from both sides -1x=7 divide both sides by -1 x=-7
2x+1 because -2 +3 = 1
x + 3 + 2x = x + 9 x + 2x + 3 = x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 2x + 3 = 9 2x + 3 - 3 = 9 - 3 2x + 3 - 3 = 9 - 3 2x = 9 -3 2x = 6 2x/2 = 6/2 2x/2 = 6/2 x = 6/2 x = 3
2x-1=-32x=-3+1x=-2/2x=-1
(2x+3)(x-2)
(2x + 3)(x - 2)
y = 2x + 1 1. Make a table: x = -2; y = -3y = 2x + 1y = 2(-2) + 1 = -4 + 1 = -3 x = -1; y = -1y = 2x + 1y = 2(-1) + 1 = -2 + 1 = -1x = 0; y = 1y = 2x + 1y = 2(0) + 1 = 0 + 1 = 1 x = 1; y = 3y = 2x + 1y = 2(1) + 1 = 2 + 1 = 3 x = 2; y = 5y = 2x + 1y = 2(2) + 1 = 4 + 1 = 5 2. Plug the points (-2, -3), (-1, -1), (0, 1), (1, 3), and (2, 5) in a xy-coordinate system. 3. Draw a line which passes through those points. Thus, the line drawn is the graph of the function y = 2x + 1
y = x^5 + x^3 + x^2 + x y' = 5x^(5 - 1) + 3x^(3 - 1) + 2x^(2 -1) + 1x^(1 - 1) (note x^1 = x and x^0 = 1) y' = 5x^4 + 3x^2 + 2x + 1
This equals 3x+3 also written as 3(x+1). If you mean a linear equation like 3x + 3 = 0, then the solution is x = -1
f(x) = √(2x -3) f(x) = (2x - 3)^(1/2) f'(x) = (1/2)[(2x - 3)^(1/2 - 1)](2) f'(x) = (2x - 3)^(-1/2) f'(x) = 1/[(2x - 3)^(1/2)] f'(x) = 1/√(2x -3)
3+4x+2-2x=2x+5
x = 1 ------------- 3 = 2x + 1 -1 -1 2=2x /2 /2 1=x
2x + 3 = xSubtract 3 from both sides so that...2x = x - 3Subtract x from both sides so that...2x - x = -3Now you have to simplify the left side so that it equals...x(2-1) = -3Now divide both sides by (2-1), the equation should now look like...x = -3/(2-1)x = -3/1x = -3Now obviously, you could have made (2-1) into 1 and left it as 1x = -3 so x = -3, but if the inside of that equation equaled something such as... (21-13) or something, you need to know you take the entire ( ) over to the other side. Also, don't forget to check your answer2(-3) + 3 = (-3)solved, it equals...-3 = -3 so it is correct.
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