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(x + 3)(3x - 2)
(x - 2)(2x + 7)
It is: (2x+3)(3x-8) when factored
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
3x2 + 2x - 8 = 0 is a quadratic equation.