(x + 3)(3x - 2)
(x - 2)(2x + 7)
It is: (2x+3)(3x-8) when factored
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
3x2 + 2x - 8 = 0 is a quadratic equation.
x(3x - 2)
(x + 3)(3x - 2)
(x - 2)(2x + 7)
2(2x-11)(3x+5)
It is: (2x+3)(3x-8) when factored
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
3x2 + 2x - 8 = 0 is a quadratic equation.
3x2 - 2x - 5 = (3x - 5)(x + 1) = 0 gives a solution of x = 5/3 or -1. Was that what you wanted?
The factors are -1(2x + 1)(3x + 4)
2x - 3x = -x
3x squared - x squared = 2x squared
2x squared minus 4