The expression (2x^2 - 3x) is a quadratic polynomial in standard form, where (2x^2) represents the quadratic term and (-3x) is the linear term. To factor it, you can take out the common factor (x), resulting in (x(2x - 3)). This expression can be analyzed for its roots or further manipulated depending on the context.
(x - 2)(2x + 7)
It is: (2x+3)(3x-8) when factored
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
3x2 + 2x - 8 = 0 is a quadratic equation.
2x squared minus 4
x(3x - 2)
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
(x - 2)(2x + 7)
2(2x-11)(3x+5)
It is: (2x+3)(3x-8) when factored
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
3x2 + 2x - 8 = 0 is a quadratic equation.
3x2 - 2x - 5 = (3x - 5)(x + 1) = 0 gives a solution of x = 5/3 or -1. Was that what you wanted?
The factors are -1(2x + 1)(3x + 4)
2x squared minus 4
2x - 3x = -x
It is: (3x+4)(2x-3) when factored