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2x+y=1
Solve for y.2x+y=5*subtract 2x from both sides*2x+y-2x=5-2xy=-2x+5 / y=5-2x
-3
If: y = 2x then y² = 4x² If: x² + y² - 8x - y + 5 = 0 then x² + 4x² - 8x - 2x + 5 = 0 → 5x² - 10x + 5 = 0 → x² - 2x + 1 = 0 → (x - 1)² = 0 → x = 1 → y = 2x = 2 × 1 = 2 → point of contact is at (1, 2)
X = 0 (zero) Y = -1 (neg 1)
-2x = y^5 or y^5 = -2x y = (-2x)^(1/5)
y=2x-4 y=2x-5 y=1 1=2x-4 -2x = -5 x=2/5 the solution is (x,y) = (2/5,1)
y = 2x-5 4x-y = 7 => y = 4x-7 2x-5 = 4x-7 2x-4x = 5-7 -2x = -2 x = 1 Therefore by substituting: x = 1 and y = -3
2x+y=1
If you graph this it will be a parabola that has each end pointing down. It crosses the x-axis at: y=-2x^2+3x+5 y=-1(2x^2-3x-5) y=-1(2x-5)(x+1) y=5/2 y=-1
x= (-1/2)y-2.5
Solve for y.2x+y=5*subtract 2x from both sides*2x+y-2x=5-2xy=-2x+5 / y=5-2x
-3
2x - y -(-1) = 2x - y + 1
4
y-1 = 2(x-3) y-1 = 2x-6 y = 2x-6+1 y = 2x-5
If: y = 2x then y² = 4x² If: x² + y² - 8x - y + 5 = 0 then x² + 4x² - 8x - 2x + 5 = 0 → 5x² - 10x + 5 = 0 → x² - 2x + 1 = 0 → (x - 1)² = 0 → x = 1 → y = 2x = 2 × 1 = 2 → point of contact is at (1, 2)