34!
= 2.952 X 10^38
factorial of -1
Factorial 6 = 720
In Prolog, a simple factorial program can be defined using recursion. Here's a basic implementation: factorial(0, 1). % Base case: factorial of 0 is 1 factorial(N, Result) :- N > 0, N1 is N - 1, factorial(N1, Result1), Result is N * Result1. % Recursive case You can query the factorial of a number by calling factorial(N, Result). where N is the number you want to compute the factorial for.
Factorial(0), or 0! = 1.
1.8333
34 factorial = 295,232,799,039,604,140,847,618,609,643,520,000,000.
1176.4706
Well, isn't that a happy little math problem! When we look at the unit digit of powers of numbers, we focus on the cyclical pattern they follow. The unit digit of 3 raised to any power follows a pattern: 3, 9, 7, 1, and then repeats. So, to find the unit digit of 3 to the power of 34 factorial, we look for the remainder when 34 factorial is divided by 4, which is 2. Therefore, the unit digit of 3 to the power of 34 factorial is 9.
The value of 9 factorial plus 6 factorial is 363,600
It is 4060.
factorial of -1
27 factorial = 10,888,869,450,418,352,160,768,000,000
1 factorial = 1
Factorial 6 = 720
Factorial 65 = 8247650592082470666723170306785496252186258551345437492922123134388955774976000000000000000
18 factorial is 6,402,373,705,728,000.
Zero factorial = 1