If you know that n = 15, substitute 15 for n and solve: n + 3 - 9 15 + 3 - 9 9
3 + 9 = 12
n = sqrt 9
-3(n-5)=24 -3n + 15 = 24 -3n= 24-15 -3n = 9 n=9/-3 n=-3
If n is any prime number and a² is divisible by n, then n will also divide a. Consider that 'n' exists as a prime number. If n divides a² then n also divides a. Let, n = 3 and a = 9 a² = 9² a² = 81 Here , 81/3 = 27 n divides a² Now, 9/3 = 3 Here, n also divides a.
If you know that n = 15, substitute 15 for n and solve: n + 3 - 9 15 + 3 - 9 9
3 + 9 = 12
9 - n 12 = -3
N=9
3 is a prime n but 9
6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3
If you mean: -3(n+5) = 12 then n works out as -9 because -3(-9+5) = 12
Plug 9 as n in this formula: n(n-3)/2
N=3
n = sqrt 9
-3(n-5)=24 -3n + 15 = 24 -3n= 24-15 -3n = 9 n=9/-3 n=-3
If n is any prime number and a² is divisible by n, then n will also divide a. Consider that 'n' exists as a prime number. If n divides a² then n also divides a. Let, n = 3 and a = 9 a² = 9² a² = 81 Here , 81/3 = 27 n divides a² Now, 9/3 = 3 Here, n also divides a.