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p=b+3a+c p-3a-c=b+3a-3a+c-c p-3a-c=b b=p-3a-c
(1) x/12=a+9, where a is an integer (2) x/18=b+9, where b is an integer 3x(1) + 2x(2) gives 3x/36 + 2x/36 = 5x/36 = 3a+27+2b+18 = 3a+2b+45 5x/36=3a+2b+45 x=36(3a+2b+45)/5 x=36(3a+2b)/5+9 as 36 is not divisible by 5 then 3a+2b should be divisible by 5 then the smallest solution is a=0 and b=0 and x=9
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(x + 3)(a + b)
If a + b = 6, what is the value of 3a + 3b?