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(1) x/12=a+9, where a is an integer

(2) x/18=b+9, where b is an integer

3x(1) + 2x(2) gives

3x/36 + 2x/36 = 5x/36 = 3a+27+2b+18 = 3a+2b+45

5x/36=3a+2b+45

x=36(3a+2b+45)/5

x=36(3a+2b)/5+9

as 36 is not divisible by 5 then 3a+2b should be divisible by 5

then the smallest solution is a=0 and b=0

and x=9

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13y ago

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