(1) x/12=a+9, where a is an integer
(2) x/18=b+9, where b is an integer
3x(1) + 2x(2) gives
3x/36 + 2x/36 = 5x/36 = 3a+27+2b+18 = 3a+2b+45
5x/36=3a+2b+45
x=36(3a+2b+45)/5
x=36(3a+2b)/5+9
as 36 is not divisible by 5 then 3a+2b should be divisible by 5
then the smallest solution is a=0 and b=0
and x=9
Try 30
12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.
The remainder of any division MUST be smaller than the divisor. So no number divided by 10 or 7 can leave a remainder of 12. So review your question and post it when it makes sense.
51.8333
0.6667
Try 30
12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.
36 divided by 28 would be 1 remainder 8and44 divided by 32 would be 1 remainder 12
66 66/16 = 4 and a remainder of 2 66/18 = 3 and a remainder of 12
12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.
26
12
The remainder of any division MUST be smaller than the divisor. So no number divided by 10 or 7 can leave a remainder of 12. So review your question and post it when it makes sense.
6.6667
23.0833
6
51.8333