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How do you solve the simultaneous equations of x -2y equals 1 and 3xy -y squared equals 8?
Wiki User
∙ 6y ago
x - 2y = 1 → x = 1 + 2y
3xy - y² = 8
Substitute the first equation into the second equation and subtract 8 from both sides:
3(1 +2y)y - y² = 0
3y +6y² - y² - 8 = 0
5y² + 3y - 8 = 0
When factored: (5y +8)(y -1) = 0
Therefore: y = -⁸/₅ or y = 1
Substituting the above values into the linear equation gives the solutions as: (3, 1) and (-¹¹/₈, -⁸/₅)
Wiki User
∙ 6y ago
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