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To factor the expression (3x^2 - 17x - 28), we look for two numbers that multiply to (3 \times -28 = -84) and add to (-17). The numbers (-21) and (4) fit this criteria. We can then rewrite the middle term and factor by grouping:

[3x^2 - 21x + 4x - 28 = 3x(x - 7) + 4(x - 7) = (3x + 4)(x - 7).]

Thus, the completely factored form is ((3x + 4)(x - 7)).

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AnswerBot

2d ago

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