Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
x(x - 13)(x - 1)
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
14x2 - 39x - 35 = (7x + 5)(2x - 7)
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
(2x+5)(7x-3)=14x2 +29x-15
28
14x2 + 15x + 4 = (7x + 4)(2x +1)
14x2
(2x - 7)(7x + 5)
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
14x2 - 5x + 1 = 2 : 14x2 - 5x - 1 = 0 Solving for the roots of a quadratic equation gives, x = [5 ± √(52 + 4x14)] ÷ 28 = (5 ± 9) ÷ 28 x = 14/28 = 1/2 and x = -4/28 = -1/7.
142 that's it duhhh
(7x - 8)(2x - 7)
(14x2)-9
x(x - 13)(x - 1)