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3x + 2 = 0 3x = -2 x = -2/3
The number of diagonals for a shape with x sides is (x²-3x)/2 The number of sides is x You want to know if x is ever less than (x²-3x)/2 or else (x²-3x)/2 - x > 0 (x² - 3x) / 2 - x > 0 (x² - 3x)/2 - (2x)/x > 0 x² - 3x - 2x > 0 x² - 5x > 0 x(x-5)>0 This only true if x<0 or x>5, and since a polygon cannot have less than 2 sides, x<0 is meaningless. This means that if x<5 then the number of diagonals is less than the number of sides, equal for x=5, and more for x>5. ■
Standard Form for a linear equation is Ax + By = C, where B is not = 0, A is >=0 and A is an integer.Sometimes ax + by + c = 0 is used instead.y = 2-3x y + 3x +2. Presto!
x3+3x2+3x+2 divided by x+2 equals x2+x+1
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)