-4 + 2y = 242y + 4 = 242y + 4 - 4 = 24 - 42y + 4 - 4 = 24 - 42y = 24 - 42y = 202y/2 = 20/22y/2 = 20/2y = 20/2y = 10Therefore the y-intercept is at (0,10) or has a value of 10
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
2y + 3 = 42y = 4 - 32y = 1divide both sides of the equation by 22y/2 = 1/2y = 1/2 in fractionory = 0.50 in decimal
-3x + 2y = -4There are lots of different ways to write it.Here are a few:-3x = -2y - 43x = 2y + 42y = 3x - 4-2y = -3x + 4x = 2y/3 + 4/3y = 3x/2 - 2
Make the equations contain an equal co-efficient of x: first multiplied by 7 = -14x + 42y = 42 second multiplied by 2 = -14x + 16y = -10 Subtract leaving 26y = 52 y = 2 -2x + 12 = 6 -2x = -6 x = 3 Check these values in the two original equations.
Reorder the terms: -5 + 42y + 27y2 Factor a trinomial. (-5 + -3y)(1 + -9y)
51
-4 + 2y = 242y + 4 = 242y + 4 - 4 = 24 - 42y + 4 - 4 = 24 - 42y = 24 - 42y = 202y/2 = 20/22y/2 = 20/2y = 20/2y = 10Therefore the y-intercept is at (0,10) or has a value of 10
Infinite number of solutions
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
2y + 3 = 42y = 4 - 32y = 1divide both sides of the equation by 22y/2 = 1/2y = 1/2 in fractionory = 0.50 in decimal
Let the amount that Eks has = X.Let the amount that Wye has = Y.X = Y + 14.X + Y = 56(Y + 14) + Y = 562Y + 14 = 562Y = 42Y = 21 ===> X = 35
-3x + 2y = -4There are lots of different ways to write it.Here are a few:-3x = -2y - 43x = 2y + 42y = 3x - 4-2y = -3x + 4x = 2y/3 + 4/3y = 3x/2 - 2
Coefficients are numbers. Find the GCF of the numbers and divide them by it.Example: 30x + 42yFind the GCF of 30 and 42.Factor them.2 x 3 x 5 = 302 x 3 x 7 = 42Select the common factors.2 x 3 = 6, the GCF30/6 = 542/6 = 730x + 42y = 6(5x + 7y)
We have x and y where 1. y - x = 1 2. 4x - 2y = 82 Solve simultaneously by eliminating y, to get 2x = 84 x = 42y = 43. ---- Arguably, a 'difference of 82' could also mean that 4x - 2y = -82 In this case, we get 2x = -80 x = -40, y = -39
Make the equations contain an equal co-efficient of x: first multiplied by 7 = -14x + 42y = 42 second multiplied by 2 = -14x + 16y = -10 Subtract leaving 26y = 52 y = 2 -2x + 12 = 6 -2x = -6 x = 3 Check these values in the two original equations.
Lets look at an example. In the expression 21x+42y x is a litteral coefficient of 21 and y is a literal coefficent of 42. We could write this as 21(x+2y) so we add the literal coefficients, well we add one of them to 2 times the other one. if you had 3x+5y, there is nothing you can really do to add these literal coefficients. How about a multiplication problem, 3xy(2xy)=6x^2y^2 so we multiply the literal coefficients. So the answer is it depends on the problems, sometimes we add the, sometimes we multiply them, sometimes we divide them and sometimes we can not do anything!