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₄₉C₅ = the number of ways a group of 5 items can be chosen from a selection of 49. As a group it does not matter in which order the 5 are selected.
It is calculated as:
₄₉C₅ = 49! / ((49-5)! 5!) = 49! / (44! 5!) = 49 × 48 × 47 × 46 × 45 / 5 × 4 × 3 × 2 × 1 = 1,906,884
(The font used to display Answers has a very bad exclamation mark (!) which looks like a vertical bar. 49! is 49 factorial and 49! = 49 × 48 × 47 × ... × 3 × 2 × 1)
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How many 4 number combinations using 5 numbers?
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
How do you turn 81 degrees Fahrenheit to centigrades?
81 deg F Subtract 32: 81 - 32 = 49 Multiply by 5: 49*5 = 245 Divide by 9: 245/9 = 27.22... deg C
C program to print all combinations of a 4-digit number?
#include<stdio.h> int main() { int a,b,c,d; for(a=1; a<5; a++) { for(b=1; b<5; b++) { for(c=1; c<5; c++) { for(d=1; d<5; d++) { if(!(a==b a==c a==d b==c b==d c==d)) printf("dd\n",a,b,c,d); } } } } return 0; }
If you have 5 letters how many combinations can you make?
Suppose the 5 letters are A, B, C, D and E. The letter A can either be in the combination or not: 2 options for A. With each of these options, B can either be in the combination or not: 2 options for B - making 2*2 options so far. With each of the options so far, C can either be in the combination or not: 2 options for C - making 2*2*2 options so far. and so on. So for 5 letters there are 25 = 32 combinations. However, one of these is the combination that excludes each of the 5 letters - ie the null combination. Excluding the null combination gives the final answer of 31 combinations.
What is minus 45 celsius in Fahrenheit?
Start by taking the number in Celsius and multiply it by 9. Then divide that number by 5, and then add 32. This is how you convert Celsius to Fahrenheit or use the equation F = (9/5)C + 32In this case, the answer is about -49 degrees Fahrenheit.
