₄₉C₅ = the number of ways a group of 5 items can be chosen from a selection of 49. As a group it does not matter in which order the 5 are selected.
It is calculated as:
₄₉C₅ = 49! / ((49-5)! 5!) = 49! / (44! 5!) = 49 × 48 × 47 × 46 × 45 / 5 × 4 × 3 × 2 × 1 = 1,906,884
(The font used to display Answers has a very bad exclamation mark (!) which looks like a vertical bar. 49! is 49 factorial and 49! = 49 × 48 × 47 × ... × 3 × 2 × 1)
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
81 deg F Subtract 32: 81 - 32 = 49 Multiply by 5: 49*5 = 245 Divide by 9: 245/9 = 27.22... deg C
#include<stdio.h> int main() { int a,b,c,d; for(a=1; a<5; a++) { for(b=1; b<5; b++) { for(c=1; c<5; c++) { for(d=1; d<5; d++) { if(!(a==b a==c a==d b==c b==d c==d)) printf("dd\n",a,b,c,d); } } } } return 0; }
Suppose the 5 letters are A, B, C, D and E. The letter A can either be in the combination or not: 2 options for A. With each of these options, B can either be in the combination or not: 2 options for B - making 2*2 options so far. With each of the options so far, C can either be in the combination or not: 2 options for C - making 2*2*2 options so far. and so on. So for 5 letters there are 25 = 32 combinations. However, one of these is the combination that excludes each of the 5 letters - ie the null combination. Excluding the null combination gives the final answer of 31 combinations.
Start by taking the number in Celsius and multiply it by 9. Then divide that number by 5, and then add 32. This is how you convert Celsius to Fahrenheit or use the equation F = (9/5)C + 32In this case, the answer is about -49 degrees Fahrenheit.
If the question concerned the number of combinations of three different coins, the answer is 23-1 = 7. If the coins are a,b,and c, the combinations are a, b, c, ab, ac, bc, abc. If two of the coins are the same there are only 5 combinations and if all three are the same there are 3.
c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
The pass rate for GCSE Computing is a minimum of grade C.
Lux Video Theatre - 1950 The Bride Came C-O-D- 5-49 was released on: USA: 28 July 1955
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5 digit combinations for numbers 1 to 50= 50 C 5N!= 1x2x3x4x...x (N-1) x N= (50!)/(45!x5!) =(50x49x...x2x1)/((45x44x...x2x1)(5x4x3x2x1))=(50x49x48x47x46)/(5x4x3x2)=254251200/120 =21187602118760 combinations
C 5 2 = 5! / (2! x 3!) = (5x4x3x2x1) / (2x1 x 3x2x1) = 10
81 deg F Subtract 32: 81 - 32 = 49 Multiply by 5: 49*5 = 245 Divide by 9: 245/9 = 27.22... deg C
They are all programming languages.
C
c is platform dependent