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₄₉C₅ = the number of ways a group of 5 items can be chosen from a selection of 49. As a group it does not matter in which order the 5 are selected.
It is calculated as:
₄₉C₅ = 49! / ((49-5)! 5!) = 49! / (44! 5!) = 49 × 48 × 47 × 46 × 45 / 5 × 4 × 3 × 2 × 1 = 1,906,884
(The font used to display Answers has a very bad exclamation mark (!) which looks like a vertical bar. 49! is 49 factorial and 49! = 49 × 48 × 47 × ... × 3 × 2 × 1)
What else can I help you with?
How many 4 number combinations using 5 numbers?
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
How many three digit whole numbers have the sum of their digits equal five?
To find the number of three-digit whole numbers where the sum of the digits equals five, we can represent the three-digit number as (abc), where (a), (b), and (c) are the digits and (a \neq 0) (since (a) is the hundreds place). The equation is (a + b + c = 5). The possible values for (a) (from 1 to 5) lead us to calculate combinations for each case. For each value of (a): (a = 1): (b + c = 4) → (5 combinations: (0,4), (1,3), (2,2), (3,1), (4,0)) (a = 2): (b + c = 3) → (4 combinations: (0,3), (1,2), (2,1), (3,0)) (a = 3): (b + c = 2) → (3 combinations: (0,2), (1,1), (2,0)) (a = 4): (b + c = 1) → (2 combinations: (0,1), (1,0)) (a = 5): (b + c = 0) → (1 combination: (0,0)) Adding these combinations gives a total of (5 + 4 + 3 + 2 + 1 = 15) three-digit whole numbers with the sum of their digits equal to five.
How many combinations of 3 numbers are there in 5 numbers?
To find the number of combinations of 3 numbers from a set of 5 numbers, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 5 ) and ( k = 3 ). Plugging in the values, we get ( C(5, 3) = \frac{5!}{3!(5-3)!} = \frac{5 \times 4}{2 \times 1} = 10 ). Therefore, there are 10 combinations of 3 numbers from a set of 5 numbers.
How many combinations of five numbers are possible from 8?
To find the number of combinations of five numbers from a set of eight, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). In this case, ( n = 8 ) and ( k = 5 ). Thus, ( C(8, 5) = \frac{8!}{5!(8-5)!} = \frac{8!}{5!3!} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56 ). Therefore, there are 56 possible combinations.
How do you turn 81 degrees Fahrenheit to centigrades?
81 deg F Subtract 32: 81 - 32 = 49 Multiply by 5: 49*5 = 245 Divide by 9: 245/9 = 27.22... deg C
How many combinations of coins in 3?
If the question concerned the number of combinations of three different coins, the answer is 23-1 = 7. If the coins are a,b,and c, the combinations are a, b, c, ab, ac, bc, abc. If two of the coins are the same there are only 5 combinations and if all three are the same there are 3.
How do you solve the equation c plus c plus 1 equals 49?
c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24
How many 4 number combinations using 5 numbers?
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
How many three digit whole numbers have the sum of their digits equal five?
To find the number of three-digit whole numbers where the sum of the digits equals five, we can represent the three-digit number as (abc), where (a), (b), and (c) are the digits and (a \neq 0) (since (a) is the hundreds place). The equation is (a + b + c = 5). The possible values for (a) (from 1 to 5) lead us to calculate combinations for each case. For each value of (a): (a = 1): (b + c = 4) → (5 combinations: (0,4), (1,3), (2,2), (3,1), (4,0)) (a = 2): (b + c = 3) → (4 combinations: (0,3), (1,2), (2,1), (3,0)) (a = 3): (b + c = 2) → (3 combinations: (0,2), (1,1), (2,0)) (a = 4): (b + c = 1) → (2 combinations: (0,1), (1,0)) (a = 5): (b + c = 0) → (1 combination: (0,0)) Adding these combinations gives a total of (5 + 4 + 3 + 2 + 1 = 15) three-digit whole numbers with the sum of their digits equal to five.
How many combinations of 3 numbers are there in 5 numbers?
To find the number of combinations of 3 numbers from a set of 5 numbers, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 5 ) and ( k = 3 ). Plugging in the values, we get ( C(5, 3) = \frac{5!}{3!(5-3)!} = \frac{5 \times 4}{2 \times 1} = 10 ). Therefore, there are 10 combinations of 3 numbers from a set of 5 numbers.
What is the pass rate for GCSE Computing?
The pass rate for GCSE Computing is a minimum of grade C.
What are the release dates for Lux Video Theatre - 1950 The Bride Came C-O-D- 5-49?
Lux Video Theatre - 1950 The Bride Came C-O-D- 5-49 was released on: USA: 28 July 1955
What did doug engelbart invented things that make computing esier for us?
C++, JAVA, VB.NET, Python, Fortran, PHP and HTML 5
How many combinations of five numbers are possible from 8?
To find the number of combinations of five numbers from a set of eight, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). In this case, ( n = 8 ) and ( k = 5 ). Thus, ( C(8, 5) = \frac{8!}{5!(8-5)!} = \frac{8!}{5!3!} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56 ). Therefore, there are 56 possible combinations.
How many 5 digit combinations for numbers 1 50?
5 digit combinations for numbers 1 to 50= 50 C 5N!= 1x2x3x4x...x (N-1) x N= (50!)/(45!x5!) =(50x49x...x2x1)/((45x44x...x2x1)(5x4x3x2x1))=(50x49x48x47x46)/(5x4x3x2)=254251200/120 =21187602118760 combinations
How many different combinations of 2 dvds are possibles if Amy has 5 dvds?
C 5 2 = 5! / (2! x 3!) = (5x4x3x2x1) / (2x1 x 3x2x1) = 10
How do you turn 81 degrees Fahrenheit to centigrades?
81 deg F Subtract 32: 81 - 32 = 49 Multiply by 5: 49*5 = 245 Divide by 9: 245/9 = 27.22... deg C
