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To simplify the expression (4x^{3 - 9} \cdot 15 \cdot 2x^{3 - 4x} \cdot 2^{-7x}), we first combine the coefficients: (4 \cdot 15 \cdot 2 = 120). Next, we simplify the powers of (x): (x^{(3 - 9) + (3 - 4x) - 7x} = x^{-6 - 11x}). Thus, the expression simplifies to (120x^{-6 - 11x}).
What else can I help you with?
10x2 plus 27x - 28?
(5x - 4)(2x + 7)
Is there a solution for 2x-y equals 3 4x-2y equals 6?
2x-y=34x-2yy=36xas we have 2x-y=6so, using y=36xwe have -34x=6so,x=-(6/34)and y=-(216/34)Another Answer:-Yes because x = 1.5 and y = 0
What is 2x plus 32x plus 3?
That's pretty easy. Just add the like terms (2x and 32x) and keep the 3. You get 34x plus 3.
3 2x-4 plus 2 x plus 7 6 answer?
The answer to the equation 3 2x-4 plus 2 x plus 7 6 is 34x + 72.
What is the product of (3x2 - 2x - 7)(9x2 plus 8x plus 6)?
The answe is 27x^4 + 6x^3 - 61x^2 - 68x - 42
In Algebra 2 what is 34x-2x-723x-5?
-691x - 5
82-2x equals 34x plus 22 what is x?
x=1.875
10x2 plus 27x - 28?
(5x - 4)(2x + 7)
How do you factor 2x2-27x plus 36?
(2x - 3)(x - 12)
Is there a solution for 2x-y equals 3 4x-2y equals 6?
2x-y=34x-2yy=36xas we have 2x-y=6so, using y=36xwe have -34x=6so,x=-(6/34)and y=-(216/34)Another Answer:-Yes because x = 1.5 and y = 0
How can you simplify x2 plus 2x-35x2 plus 4x-21?
It is: 4x -34x^2 -21 simplified
What is 2x plus 32x plus 3?
That's pretty easy. Just add the like terms (2x and 32x) and keep the 3. You get 34x plus 3.
Algebra 2 help 34x-2x-723x-5?
That would be = 34-725x-5 = 759x-5 And that would be the answer.
3 2x-4 plus 2 x plus 7 6 answer?
The answer to the equation 3 2x-4 plus 2 x plus 7 6 is 34x + 72.
When is Quotient when (x plus 3) is Divided into the polynomial 2x to the power 2 x-15?
Assuming that he quadratic is 2x^2 + x - 15, the quotient is 2x - 5.
How do you factor the trinomial completely 18x3 29x 3x?
I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1) 18x3 + 29x2 + 3x factor x = x(18x2 + 29x + 3) write 29x as 27x + 2x = x(18x2 + 27x + 2x + 3) group by two and factor each group = x[(18x2 + 27x) + (2x + 3)] = x[9x(2x + 3) + 1(2x + 3)] continue factoring = x(2x + 3)(9x + 1) Or since (18)(3) = 54 and (27)(2) = 54 then write: = x(18x2 + 29x + 3) = x[(18x + 27)/9][(18x + 2)/2] = x(2x + 3)(9x + 1)
What is the product of (3x2 - 2x - 7)(9x2 plus 8x plus 6)?
The answe is 27x^4 + 6x^3 - 61x^2 - 68x - 42
