3y2 - 2y + 6xy - 4x = y(3y - 2) + 2x(3y - 2) = (y + 2x)*(3y - 2)
Yes and x = 2+square root of 6 or x = 2-square root of 6
4x + 20
perimeter of a square is 4x square that term (4x)(4x)and it gives you 16x2
x2 - 4x - 21 = (x-7)(x+3)
6xy+9y2
xy(7+2y-3x)-6xy
3y2 - 2y + 6xy - 4x = y(3y - 2) + 2x(3y - 2) = (y + 2x)*(3y - 2)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 92 = (3x - y - 9)(3x - y + 9)
4x - 2x = 2x
4
Yes and x = 2+square root of 6 or x = 2-square root of 6
x^2(2x - 3y)(4x^2 + 6xy + 9y^2)
3x2y - 4xy + 4x
35
The square root of 4x^2 is solved by first doing the square root of 4. This is plus or minus two - because -2 x -2=4. The square root of x^2 is x. So the answers are 2x or -2x. If your question was (4x)^2, then the answer would be 4x.
4x + 20