4y > 16 divide by 6 both sides;
y > 4
This inequality is true for all y greater than 4 (4 is not a solution).
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y > 3 Treat the greater than sign [a bit] like an equals sign to solve: 4y - 3 > 9 ⇒ 4y > 12 [add 3 to each side] ⇒ y > 3 [divide each side by 4]
2x + 4y = 16 <=> 2x + 4y - 16 = 0 2x - 4y = 0 2x - 4y = 2x + 4y - 16 -8y = -16 y = 2 Substituting the known value for y in either of the original equations enables x to be determined. 2x + (4*2) = 16 : 2x = 16 - 8 : x2x = 8 : x = 4 2x - (4*2) = 0 : 2x - 8 = 0 : 2x = 8 : x = 4. The ordered pair satisfying both equations is (4,2)
....Well...if you mean 4y + 9 = 17, then the answer is 2.If you mean 4y - 9 = 17, then the answer is 6.5.
2x-4y = 16 -4y = -2x+16 y = 1/2x-4 Any equation that has a slope of 1/2 but a different intercept of -4.
First, solve for zero y2 - 4y > 5 y2 - 4y - 5 > 0 (y - 5)(y + 1) > 0 So where y = 5 and y = -1, the inequality solves for zero. We know that because the term with the highest power of y has a positive coefficient, that this is a parabola which has a limit in the negative, and is infinite in the positive. That means y is less than negative one or greater than 5. {x | x < -1 OR x > 5, x ∈ ℜ}