256.
53
No year has 51 Thursdays. A year has either 52 or 53 Thursdays. Normally it has 52 Thursdays. If it starts on a Thursday or a leap year starts on a Wednesday, there are 53 Thursdays in the year.
52 plus 1.
To find the mean of the numbers 45, 50, 47, 52, 53, 45, and 51, first add them together: 45 + 50 + 47 + 52 + 53 + 45 + 51 = 393. Then, divide the total by the number of values (7): 393 ÷ 7 = 56.14. Therefore, the mean is approximately 56.14.
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
the factors always start 1....... and so on
Just 53
51
Well, darling, the average of 51, 52, and 56 is 53. That's right, just add them all up and divide by how many numbers you have. In this case, it's as easy as pie.
53
No year has 51 Thursdays. A year has either 52 or 53 Thursdays. Normally it has 52 Thursdays. If it starts on a Thursday or a leap year starts on a Wednesday, there are 53 Thursdays in the year.
52 plus 1.
To find the mean of the numbers 45, 50, 47, 52, 53, 45, and 51, first add them together: 45 + 50 + 47 + 52 + 53 + 45 + 51 = 393. Then, divide the total by the number of values (7): 393 ÷ 7 = 56.14. Therefore, the mean is approximately 56.14.
The average of the numbers 51, 52, and 56 is 53. To get the average you would add all three numbers and then divide by three.
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
It could be 50 or 51, 52, 53 coming from a teacher.
The numbers are 51, 52 and 53.