53
No year has 51 Thursdays. A year has either 52 or 53 Thursdays. Normally it has 52 Thursdays. If it starts on a Thursday or a leap year starts on a Wednesday, there are 53 Thursdays in the year.
52 plus 1.
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
100
the factors always start 1....... and so on
Just 53
51
Oh, dude, you just add them up and divide by how many numbers there are. So, like, 51 + 52 + 56 = 159, and since there are three numbers, you divide 159 by 3 and get 53. So, the average is 53.
53
No year has 51 Thursdays. A year has either 52 or 53 Thursdays. Normally it has 52 Thursdays. If it starts on a Thursday or a leap year starts on a Wednesday, there are 53 Thursdays in the year.
52 plus 1.
The average of the numbers 51, 52, and 56 is 53. To get the average you would add all three numbers and then divide by three.
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
It could be 50 or 51, 52, 53 coming from a teacher.
The numbers are 51, 52 and 53.
5 + 26 + 5 + 6 + 8 + 68 + 53 + 556 + 565252 + 52 = 566031