Q: What are three consecutive numbers whose sum is 156?

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let the three numbers be: n-1, n, n+1 their sum is equal to 3n 468=3n which means that n=156 the three numbers are 155, 156, 157

156 and 158 sum to 314.

x + (x+1) + (x+2) = -153 3x + 3 = -153 3x = -156 x = -52 The three numbers are therefore: -52,-51 & -50.

If the sum of 2 numbers is 25 and their product is 156, the numbers are 12 and 13.

12 and 13

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X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers

let the three numbers be: n-1, n, n+1 their sum is equal to 3n 468=3n which means that n=156 the three numbers are 155, 156, 157

The numbers are 156 and 157.

12 & 13

132, 156 and 204

Let's denote the smallest of the three consecutive numbers as "x". The second number would then be x+1, and the third number would be x+2. Since the sum of the three numbers is 156, we can set up the equation as x + (x+1) + (x+2) = 156. Simplifying the equation, we get 3x + 3 = 156. Solving for x, we find that the smallest number is x = 51.

Let the middle number of the three be n. Then the three consecutive numbers are n-1, n, n+1. Their sum is n-1 + n + n+1 = 3n Their average is 3n / 3 = n The difference between their sum and their average is 3n-n = 2n 2n = 156 => n = 78. Thus the three numbers are 77, 78, 79

12, 13

12 and 13

156

156 and 158 sum to 314.

54 and 56