x2 - x10 + x5 - x12 - x3
Given that 52 - x2 + x = 10, then -52 + x2 - x + 10 = x2 - x - 42 = (x - 7)(x + 6) = 0. Therefore, x = 7 or -6.
60 square feet
Y = X2 + 18X + 52 set to 0 X2 + 18X + 52 = 0 subtract 52 from each side X2 + 18X = - 52 now, halve the coefficient of the variable term (18), square it and add it to both sides X2 + 18X + 81 = - 52 + 81 now, factor on left and gather terms on right (X + 9)2 = 29 (X + 9)2 - 29 = 0 ---------------------------vertex form
The new mean would be 7. The mean is the average of the data. (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10=21 [(x1/3)+(x2/3)+(x3/3)+(x4/3)+(x5/3)+(x6/3)+(x7/3)+(x8/3)+(x9/3)+(x10/3)]/10=? [(1/3)(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)]/10=? [(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10]/3= 21/3=7
x2 - x10 + x5 - x12 - x3
x2 + y - 52 = 30x2 - x2 + y - 52 + 52 = - x2 + 30 + 52y = -x2 + 82Since a = -1, the parabola open downward, and crosses the x-axis at x = +&- sq.root of 82.0 = -x2 + 820 - 82 = -x2 + 82 - 82-82 = -x282 = x2+&- sq.root of 82 = x
Approximately 96.4 bushels.
Given that 52 - x2 + x = 10, then -52 + x2 - x + 10 = x2 - x - 42 = (x - 7)(x + 6) = 0. Therefore, x = 7 or -6.
The cheat codes are x2 FfAs23T x10 dof2vd2
60 square feet
Y = X2 + 18X + 52 set to 0 X2 + 18X + 52 = 0 subtract 52 from each side X2 + 18X = - 52 now, halve the coefficient of the variable term (18), square it and add it to both sides X2 + 18X + 81 = - 52 + 81 now, factor on left and gather terms on right (X + 9)2 = 29 (X + 9)2 - 29 = 0 ---------------------------vertex form
The new mean would be 7. The mean is the average of the data. (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10=21 [(x1/3)+(x2/3)+(x3/3)+(x4/3)+(x5/3)+(x6/3)+(x7/3)+(x8/3)+(x9/3)+(x10/3)]/10=? [(1/3)(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)]/10=? [(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10]/3= 21/3=7
Forty, or a piece of lumber 2 in x2 in x10 ft long.
8
Complete the squares: x2 - 10x + 25 + y2 + 4y + 4 - 52 = 25 + 4 = 29 x2 - 10x + 25 + y2 + 4y + 4 = 52 + 29 = 81 So the radius is sqrt(81) = 9
29000000