f+7=12 is the equation so, f=5
14x
If: 5f+3 = 28 then f = 5 because (5*5)+3 = 28
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
F = 9/5 C + 32 = (9/5) x 10 + 32 = 18 + 32 = 50
f+7=12 is the equation so, f=5
s=5 f+s=? Substitute 5 in for s.Substitute 1 in for f.f+s=f+5f=11+5 ={6}
19 = f + 5 Subtract 5 from both sides: 14 = f
1/3 + f = 3/4 subtract 1/3 from both sides: f = 3/4 - 1/3 = 9/12 - 4/12 = 5/12
f = 54
14x
g(x) = 5. So whatever f(x) or f(-1) is, g of that is going to be 5.
If: 5f+3 = 28 then f = 5 because (5*5)+3 = 28
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
F = 9/5 C + 32 = (9/5) x 10 + 32 = 18 + 32 = 50
Only if it's a function.
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)