4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1
2a+5a+9a = 16a
2a + 10 + 5a - 2 = (2a + 5a) + (10 - 2) = 7a + 8
It is not an equation but an algebraic expression that can be simplified to: 12b-5a
3a4 - 2a2 + 5a - 10 - 2a4 + 4a2 + 5a - 2 = a4 + 2a2 + 10a - 12 = a4 + (2a - 2)(a + 6)
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
No.
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
4a2 - 20ab2 + 25b4 (2a - 5b2)(2a - 5b2) (2a - 5b2)2
4a2 + 4ab - y2 + b2 You cannot simplify this expression because it does not contain like terms, but you can factor it such as: 4a2 + 4ab - y2 + b2 = (4a2 + 4ab + b2) - y2 = (2a + b)2 - y2 = [(2a + b) - y][(2a + b) + y]
5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1
5a
2a + 5a + 3a = 10a
2a+5a+9a = 16a
= 4a2 + 2ab 2b2
The statement is false. 5a +6 = 5a + 30 Subtract 5a from both sides: 6 = 30 and that is plain and simple rubbish!